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Firdavs [7]
3 years ago
15

Which expressions are equivalent to 5(2e+3)+8(e+4)+3 ?

Mathematics
2 answers:
Stels [109]3 years ago
5 0
2(9e+25) isidjfiekrjif
ivanzaharov [21]3 years ago
3 0

Answer:

2(9e+25)

and

50+18e

are equivalent to the given expresson

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<img src="https://tex.z-dn.net/?f=%282w%20%2B%201%29%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="(2w + 1) {}^{2} " alt="(2w +
Lynna [10]

Answer:

4w^2 +4w+1

this is the product.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
James won 9 out of 12 games in a school competition. What percent of competitions did James win
ratelena [41]
75% because 9/12 simplified is 3/4 which is 75%
5 0
3 years ago
a child should no longer play in the kid zone area when they reach 4'4" tall joe is 54" tall is he allowed to play in the kid zo
Andreyy89

Answer: No.

Step-by-step explanation: Joe is 4'6" tall. Convert 54" to feet by dividing by 12. 54/12=4.5. Half of a foot is 6 inches.

6 0
3 years ago
Inverse of y=(x/2)^2
Lady bird [3.3K]
Tell me if the answer is true or wrong

6 0
3 years ago
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