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Zigmanuir [339]
2 years ago
5

Use point-slope form − 1 = ( − 1) to find the equation of the line that passes through the point (−3,5) and has slope = −2 . Wri

te the answer in slope-intercept form = + .
Mathematics
1 answer:
Tom [10]2 years ago
8 0

Answer:

y - 5 = -2(x + 3)

Step-by-step explanation:

When you write an equation in point-slope form, you only need two things: a point and a slope.

Given:

point: (-3, 5)

slope (m): -2

The standard point-slope equation is

y - y₁ = m(x - x₁)

Plug in what you know.

y - (5) = -2(x - (-3))

Simplify.

y - 5 = -2(x + 3)

This is your equation.

Learn with another example:

brainly.com/question/24436844

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Sebastian solved the radical equation y + 1 = but did not check his solution. (y + 1)2 = y2 + 2y + 1 = –2y – 3 y2 + 4y + 4 = 0 (
Softa [21]

Answer:

There are no true solutions to the equation.

Step-by-step explanation:

<u><em>The correct equation is</em></u>

y+1=\sqrt{-2y-3}

Solve for y

squared both sides

(y+1)^2=(-2y-3)

(y^2+2y+1)=(-2y-3)

y^2+2y+1+2y+3=0

y^2+4y+4=0

(y+2)(y+2)=0

y=-2

<em>Verify</em>

substitute the value of y in the original expression

-2+1=\sqrt{-2(-2)-3}

-1=1 ----> is not true

therefore

There are no true solutions to the equation.

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It's D
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