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Masteriza [31]
2 years ago
14

Here is a better picture​

Mathematics
1 answer:
Sonja [21]2 years ago
3 0

Answer:all

Step-by-step explanation:so because u have done all

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A forest fire covers 2006 acres at time t equals 0. the fire is growing at a rate of 8 startroot t endroot acres per hour, where
MissTica
<span>Answer: We'll have to integrate the growth rate with respect to time, without forgetting the amount of area covered at the start. A = 2010 + â« 8t1/2 dt (as t goes from 0 to 24) A = 2010 + [(16/3) t3/2] (as t goes from 0 to 24) A = 2010 + 627 = 2637 acres We don't integrate the 2010 here because whatever effects of the passing of time have already taken place over that area. We just treat it as a constant and add it to the result of integration.</span>
8 0
3 years ago
∆ ABC is isosceles with AB= AC= 7.5cm and BC= 0 cm .the height AD from A to BC, is 6cm . find the area of ∆ ABC what will be the
lora16 [44]

I have attached an image of the triangle.

BC = 9 cm

Answer:

CE = 7.2 cm

Step-by-step explanation:

In the attached triangle, we see that;

AB = AC = 7.5cm

BC = 9 cm

AD = 6cm

BC = 9cm

Formula for area of triangle is given as;

A = ½bh

Where b is base and h is height.

For the ∆ ABC with BC as base,

Area = ½ × 9 × 6 = 27 m²

Similarly, For ∆ ABC with AB as base,

Area = ½ × 7.5 × CE

Now, area from earlier is 27 cm²

Thus;

½ × 7.5 × CE = 27

Multiply both sides by 2 to get;

7.5CE = 54

CE = 54/7.5

CE = 7.2 cm

3 0
3 years ago
a weed called the Raindrop Vine is known for growing at a very fast rate it can grow up to 0.75 ft per day how fast in inches pe
kari74 [83]

So we need to convert 0.75 feet to inches.

0.75 feet = 9 inches

Then we divide 9 by how many hours are in a day: 24

9/24 = 0.375

The raindrop vine can grow up to 0.375 inches per hour.


6 0
3 years ago
Read 2 more answers
How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
Point e is located at -5,2 point m is the reflection of point e what is the distance between e and m
nataly862011 [7]

Answer:

the distance is 10

Step-by-step explanation:

-5,2 to 0,0 is 5

and the refection of -5,2 is 5,2

5,2 to 0,0. is also 5

5+5=10

4 0
3 years ago
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