If It takes 60mL of 0.20M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (
), then the concentration of the carbonic acid is 0.24M
The reaction between NaOH solution and
is written below

Volume of NaOH,
= 60 ml
Volume of
, 
Molarity of
, 
Molarity of NaOH, 
Number of moles of
, 
Number of moles of NaOH, 
The mathematical equation for neutralization reaction is:

Substitute
,
,
,
= 60ml, and
into the equation above in order to solve for 

Therefore, the concentration of the carbonic acid is 0.24M
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I think cathode should be silver or gold
you can use silver nitrate solution or mercury nitrate solution
For this problem, we should use the Henry's Law formula which is written below:
P = kC
where
P is the partial pressure of the gas
k is the Henry's Law constant at a certain temperature
C is the concentration
Substituting the values,
1.71 atm = (7.9×10⁻⁴<span> /atm)C
Solving for C,
C = 2164.56 molal or 2164.56 mol/kgwater
Let's make use of density of water (</span>1 kg/1 m³) and the molar mass of NF₃ (71 g/mol).<span>
Mass of NF</span>₃ = 2164.56 mol/kg water * 1 kg/1 m³ * 1 m³/1000000 mL * 150 mL * 71 g/mol = 23.05 g