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3 years ago

How to write a balanced chemical equation for the standard formation reaction of liquid octanol?

1 answer:

3 0

To write a balanced chemical equation for the standard formation reaction of liquid octanol form the octanol from its elements — C, H, and O.

The standard enthalpy of formation of a compound is the change in enthalpy when 1 mol of the compound is formed from its constituent elements. All substances must be in their most stable states at 100 kPa and 25 °C.

write a thermochemical equation for the formation of 1 mol of octanol.

8C(s) + 9H₂(g) + ½O₂(g) → C₈H₁₇OH(l)

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It takes 60 mL of 0.20 M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (H2CO3) for the following chemical reac

irina1246 [14]

If It takes 60mL of 0.20M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid ( $H_2CO_3$ ), then the concentration of the carbonic acid is 0.24M

The reaction between NaOH solution and $H_2CO_3$ is written below

$2NaOH + H_2CO_3 \rightarrow Na_2CO_3 + 2H_2O$

Volume of NaOH, $V_B$ = 60 ml

Volume of $H_2CO_3$ , $V_A=25 ml$

Molarity of $H_2CO_3$ , $C_A=?$

Molarity of NaOH, $C_B=0.20M$

Number of moles of $H_2CO_3$ , $n_A=1$

Number of moles of NaOH, $n_B=2$

The mathematical equation for neutralization reaction is:

$\frac{C_AV_A}{C_BV_B} =\frac{n_A}{n_B}$

Substitute $C_B=0.2 M$ , $n_A=1$ , $n_B=2$ , $V_B$ = 60ml, and $V_A=25 ml$ into the equation above in order to solve for $C_A$

$\frac{C_A \times 25}{0.2 \times 60}=\frac{1}{2} \\\\50C_A=12\\\\C_B=\frac{12}{50} \\\\C_B=0.24M$

Therefore, the concentration of the carbonic acid is 0.24M

Learn more here: brainly.com/question/25943090

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2 years ago

You wish to set up an electrochemical cell that has a copper anode and an

professor190 [17]

I think cathode should be silver or gold
you can use silver nitrate solution or mercury nitrate solution

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3 years ago

Complete combustion of 6.4g of compound K produced 8.8 g of carbon dioxide and 7.2 g of water. Calculate the empirical formula o

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3 years ago

Which gas law describes the relationship between volume and pressure at a constant temperature?

Iteru [2.4K]

Boyles law is the answer.

-Steel jelly

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3 years ago

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At 25°c the henry's law constant for nitrogen trifluoride (nf3) gas in water is 7.9 × 10-4 m/atm. what is the mass of nf3 gas th

Step2247 [10]

For this problem, we should use the Henry's Law formula which is written below:

P = kC
where
P is the partial pressure of the gas
k is the Henry's Law constant at a certain temperature
C is the concentration

Substituting the values,
1.71 atm = (7.9×10⁻⁴<span> /atm)C
Solving for C,
C = 2164.56 molal or 2164.56 mol/kgwater

Let's make use of density of water (</span>1 kg/1 m³) and the molar mass of NF₃ (71 g/mol).<span>

Mass of NF</span>₃ = 2164.56 mol/kg water * 1 kg/1 m³ * 1 m³/1000000 mL * 150 mL * 71 g/mol = 23.05 g

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3 years ago