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Doss [256]
3 years ago
14

How to write a balanced chemical equation for the standard formation reaction of liquid octanol?

Chemistry
1 answer:
garri49 [273]3 years ago
3 0
To write a balanced chemical equation for the standard formation reaction of liquid octanol form the octanol from its elements — C, H, and O.

The standard enthalpy of formation of a compound is the change in enthalpy when 1 mol of the compound is formed from its constituent elements. All substances must be in their most stable states at 100 kPa and 25 °C.

write a thermochemical equation for the formation of 1 mol of octanol.

8C(s) + 9H₂(g) + ½O₂(g) → C₈H₁₇OH(l)

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If It takes 60mL of 0.20M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (H_2CO_3), then the concentration of the carbonic acid is 0.24M

The reaction between NaOH solution and H_2CO_3 is written below

2NaOH + H_2CO_3 \rightarrow Na_2CO_3 + 2H_2O

Volume of NaOH, V_B = 60 ml

Volume of H_2CO_3, V_A=25 ml

Molarity of H_2CO_3, C_A=?

Molarity of NaOH, C_B=0.20M

Number of moles of H_2CO_3, n_A=1

Number of moles of NaOH, n_B=2

The mathematical equation for neutralization reaction is:

\frac{C_AV_A}{C_BV_B} =\frac{n_A}{n_B}

Substitute  C_B=0.2 M,  n_A=1,  n_B=2,  V_B = 60ml, and  V_A=25 ml into the equation above in order to solve for C_A

\frac{C_A \times 25}{0.2 \times 60}=\frac{1}{2}  \\\\50C_A=12\\\\C_B=\frac{12}{50} \\\\C_B=0.24M

Therefore, the concentration of the carbonic acid is 0.24M

Learn more here: brainly.com/question/25943090

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For this problem, we should use the Henry's Law formula which is written below:

P = kC
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Substituting the values,
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