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3 years ago

How to write a balanced chemical equation for the standard formation reaction of liquid octanol?

1 answer:

3 0

To write a balanced chemical equation for the standard formation reaction of liquid octanol form the octanol from its elements — C, H, and O.

The standard enthalpy of formation of a compound is the change in enthalpy when 1 mol of the compound is formed from its constituent elements. All substances must be in their most stable states at 100 kPa and 25 °C.

write a thermochemical equation for the formation of 1 mol of octanol.

8C(s) + 9H₂(g) + ½O₂(g) → C₈H₁₇OH(l)

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Which phase change has more kinetic energy:boiling or melting?

Romashka-Z-Leto [24]

the phase change of boiling has more kinetic energy.

boiling is a liquid ---> gas

melting is solid ---> liquid

in a liquid, there is medium kinetic energy but when a liquid is boiled it turns into a gas and gains more kinetic energy, so there is more movement and the particles move freely as there is high KE.

in a solid, there is low kinetic energy as the particles vibrate in fixed positions. a solid gains kinetic energy when it becomes a liquid (melting) and there is medium kinetic energy.

there is a higher amount of kinetic energy when a substance is boiled.

therefore, the answer is boiling.

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3 years ago

What is a primary consumer

Ket [755]

Answer:

They eat producers

Explanation:

for example, any herbivore

3 0

3 years ago

Read 2 more answers

How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m

Pie

<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol$

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})$

$pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of acetic acid = 4.74

$[CH_3COONa]=?mol$

$[CH_3COOH]=0.200mol$

pH = 5.00

Putting values in above equation, we get:

$5=4.74+\log(\frac{[CH_3COONa]}{0.200})$

$[CH_3COONa]=0.364mol$

To calculate the mass of sodium acetate for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

$0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g$

Hence, the mass of sodium acetate that must be added is 30.23 grams

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3 years ago

What would the word equation be?

valentinak56 [21]

The problem=the equation

5 0

3 years ago

When a student chemist transferred the metal to the calorimeter, some water splashed out of the calorimeter. will this technique

Natalka [10]

Answer:

It will be reported too low.

Explanation:

To measure the specific heat of the metal (s), the calorimeter may be used. In it, the metal will exchange heat with the water, and they will reach thermal equilibrium. Because it can be considered an isolated system (there're aren't dissipations) the total amount of heat (lost by metal + gained by water) must be 0.

Qmetal + Qwater = 0

Qmetal = -Qwater

The heat is the mass multiplied by the specific heat multiplied by the temperature change. If c is the specific heat of the water:

m_metal*s*ΔT_metal = - m_water *c*ΔT_water

s = -m_water *c*ΔT_water / m_metal*ΔT_metal

So, if m_water is now less than it was supposed to be, s will be reported too low, because they are directly proportional.

5 0

3 years ago