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Elden [556K]
3 years ago
12

A nuclear chemist measures the mass defect of nickel-56 and finds it to be 0.4667 amu. Based on this number, (a) calculate the n

uclear binding energy in units of joule and (b) calculate the binding energy per nucleon in units of joule. Show the complete processes and bold the final answers.
Chemistry
1 answer:
NNADVOKAT [17]3 years ago
5 0

Answer:

See explanation

Explanation:

Number of protons = 28

Number of neutrons = 28

Mass of each proton = 1.007277 amu

Mass of 28 protons = 28 * 1.007277 amu = 28.203756 amu

Mass of each neutron = 1.008665 amu

Mass of 28 neutrons = 28 * 1.008665 amu = 28.24262 amu

mass defect of nickel-56  = 0.4667 amu

Binding energy = Δmc^2

Binding energy = 0.4667 *(3 * 10^8)^2

Binding energy =4.2 * 10^16 J

Binding energy per nucleon = 4.2 * 10^16 J/56

Binding energy per nucleon = 7.5 * 10^14 J

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