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Karo-lina-s [1.5K]

2 years ago

13

Consider two histograms that can be constructed from the frequency distribution below; the first will have 12 classes with a cla

ss width of one, and the second will have four classes with a class
width of three.

1 answer:

beks73 [17]2 years ago

8 0

Answer:

okb-joye-ngv

C O m e t o l e a r n s e x

or m a k e s e x

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20 POINTS!!!! write an example of an equation with variables on each side. state the steps you would use to isolate the variable

DENIUS [597]

3y + 2 = 5(y - 6) this is what i found i hope it helps

5 0

2 years ago

Slove algebraically<br><br>3x - 4y = -24<br>x +4y=8<br>

Vanyuwa [196]

Solve algebrically 3x - 4y = -24 and x + 4y = 8 is x = -4 and y = 3

<u>Solution:</u>

We have been given two equations which are as follows:

3x - 4y = -24 ----- eqn 1

x + 4y = 8 -------- eqn 2

We have been asked to solve the equations which means we have to find the value of ‘x’ and ‘y’.

We rearrange eqn 2 as follows:

x + 4y = 8

x = 8 - 4y ------eqn 3

Now we substitute eqn 3 in eqn 1 as follows:

3(8 - 4y) -4y = -24

24 - 12y - 4y = -24

-16y = -48

y = 3

Substitute "y" value in eqn 3. Therefore the value of ‘x’ becomes:

x = 8 - 4(3)

x = 8 - 12 = -4

Hence on solving both the given equations we get the value of x and y as -4 and 3 respectively.

5 0

2 years ago

Write down a fraction whose value lies between 3 and 4; whose denominator is a multiple of 5; whose numerator is a multiple of 1

slamgirl [31]

Answer:

33/10 and 55/15

Step-by-step explanation:

Possible denominators that are multiples of 5 less than 17 are 5, 10, 15.

Corresponding numerator ranges are [15, 20], [30, 40], and [45, 60]. In only two of these ranges are there any multiples of 11.

33 in [30, 40]

55 in [45, 60]

So, there are only two possible fractions meeting your requirement:

33/10 and 55/15

6 0

3 years ago

A three inch diameter pulley on an electric motor that runs at 1800

Bezzdna [24]

Answer:

a) 3 inch pulley: 11,309.7 radians/min

6) 6 inch pulley: 5654.7 radians/min

b) 900 RPM (revolutions per minute)

Step-by-step explanation:

Hi!

When a pulley wirh radius R rotantes an angle θ, the arc length travelled by a point on its rim is Rθ. Then the tangential speed V is related to angular speed ω as:

$V=R\omega$

When you connect two pulleys with a belt, if the belt doesn't slip, each point of the belt has the same speed as each point in the rim of both pulleys: Then, both pulleys have the same tangential speed:

$\omega_1 R_1 = \omega_2 R_2\\$

$\omega_2 = \omega_1 \frac{R_1}{R_2} =1800RPM* \frac{3}{6}= 900RPM$

We need to convert RPM to radias per minute. One revolution is 2π radians, then:

$\omega_1 = 1800*2\pi \frac{radians}{min} = 11,309.7\frac{radians}{min}$

$\omega_2 = 5654.7 \frac{radians}{min}$

The saw rotates with the same angular speed as the 6 inch pulley: 900RPM

3 0

3 years ago

Question 6 (2 points)

Orlov [11]

Answer:

Blank 1: (-7,0)

Blank 2: (-1,0)

Step-by-step explanation:

Plug x=0 into the equation and solve the resulting equation y=7 for y

Plug y=0 into the equation and solve the resulting equation 0=(x+1)(x+7) for x

6 0

2 years ago