4x-1/2=x+7 WHATS TTHE ANSWER

Which value of n makes this equation true?

jonny [76]

Answer:

the answer is A. -16

Step-by-step explanation:

3(-16)+3= -45

-45/5=

-9

5(-16)-1=-81

-81/9=

-9

-9=-9

4 0

3 years ago

Find the coordinates of the point (x, y) shown on the unit circle. X=

wel

Answer:

purrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Determine if the following triangle is a right triangle or not using the Pythagorean Theorem Converse. Triangle with side length

seraphim [82]

Answer:

A right triangle is a triangle in which one of the angles is a 90∘ angle. The "square" at the vertex of the angle indicates that it is 90 degrees. A triangle can be determined to be a right triangle if the side lengths are known.

6 0

3 years ago

13. In A ABC, if m BF is an angle bisector, find m

Tresset [83]

If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.

Given that m∠ABF=41° and BF is an angle bisector.

We are required to find the angle m∠BCE if BF is an angle bisector.

Angle bisector basically divides an angle into two parts.

If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.

In this way ∠ABC=2*∠ABF

∠ABC=2*41

=82°

In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.

∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)

∠BCE+90+82=180

∠BCE=180-172

∠BCE=8°

Hence if BF is an angle bisector then angle m∠BCE=8°.

Learn more about angles at brainly.com/question/25716982

#SPJ1

4 0

1 year ago

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. Multiply 2 by -2, which is -4.
2. Ask: Which two numbers add up to -3 and multiply to -4?
3. Answer: 1 and -4
4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: Factor out common terms in the first two terms, then in the last two terms.

 $x(2x+1)-2(2x+1)\ \textless \ 0$

Step 3: Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. Solve each of the 2 equations above:

 $x=- \frac{1}{2} ,2$

Step 5: From the values of $x$ above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: Pick a test point for each interval

For the interval $x\ \textless \ - \frac{1}{2} 
$
Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.

For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this interval.

For the interval $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)

4 0

3 years ago