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3 years ago

Help pleaseeeeee!!?’dndjfjcjdc

Mathematics

1 answer:

Vanyuwa [196]3 years ago

5 0

answer: 50°

If triangle is isosceles than L and J are same angles

3x + 20 = 4x + 10

3x-4x=10-20

-x = -10 (divide both sides by -1)

x=10

angle L=J = 3*10+20= 50

we can calculate it like this too 4*10 +10= 50

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When the author observed a sobriety checkpoint conducted by the Dutchess County Sheriff Department, he saw that 676 drivers were

jek_recluse [69]

Answer:

The probability of drivers who are not intoxicated is P(I¯) and is given as 0.99411.

Step-by-step explanation:

As the event is indicated as I for the drivers who are intoxicated, the value of I¯ is for the drivers who are not intoxicated. Its value is calculated as follows

P(I¯)=1-P(I)

P(I¯)=1-0.00589

P(I¯)=0.99411

So the probability of drivers who are not intoxicated is P(I¯) and is given as 0.99411.

6 0

4 years ago

1/1,000,000 grams = 1 what

Troyanec [42]

Answer:

It can equal anything.. You need to find a unit to convert it to.. Such as feet, or meters.

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly and at a constant rate. After 8 88 mon

Aliun [14]

Answer:

Equation for the relationship between the weight and number of months -

$W(t) = W(0) + 6 * t$

Step-by-step explanation:

Given

The initial weight of young sumo wrestler just before he decide to gain more weight is equal to $90$ kilo grams.

The new weight of young sumo wrestler after eight months is equal to $138$ kilo grams.

Weight gained by sumo wrestler during the period of eight months

$138 -90\\= 48$

The rate at which weight was gained

$\frac{48}{8}$

$6$ kilo grams per month

Let W(t) depict the weight after 8 months

t depict the time period in moths

So the equation would be

$W(t) = W(0) + 6 * t$

Where

$W(0) =$ Initial weight before 8 months

$t =$ time in months

3 0

3 years ago

You have $4.10 in nickels, dimes, and quarters. If you have twice as many dimes as quarters, and five more nickels than dimes, h

lutik1710 [3]

For this case, the first thing to do is define variables.

We have then:

x: number of nickels
y: number of dimes
z: number of quarters

We write now the system of equations:

$0.05x + 0.1y + 0.25z = 4.10\\y = 2z\\x = y + 5$

Then rewriting the equations we have:

$0.05 (2z + 5) + 0.1 (2z) + 0.25z = 4.1\\0.05 (2z + 5) + 0.1 (2z) + 0.25z = 4.1\\0.1z + 0.25 + 0.2z + 0.25z = 4.1\\0.55z = 4.1-0.25$

$z = \frac {3.85} {0.55}\\z = 7$

Then, substituting values we have:

$y = 2 (7)\\y = 14$

Finally:

$x = 14 + 5\\x = 19$

Answer:

19 nickels

14 dimes

7 quarters

6 0

4 years ago

Gabriel invests $9600 in two different accounts. The first account paid 13 %, the second account paid 6 % in interest. At the en

NeX [460]

Answer:The principal for the first account is $5000

The principal for second account is $4600

Step-by-step explanation:

The formula for simple interest is expressed as

I = PRT/100

Where

P = principal

T = time in years

R = interest rate on the principal.

Let x represent the amount invested in the first account

Let y represent the amount invested in the second account

Gabriel invests $9600 in two different accounts. This means that

x + y = 9600 - - - - - - - -1

For first account, The interest rate is 13%. The duration is one year.

Therefore

P = x

T = 1 year

R = 13%

Therefore

I = (x × 13 × 1)/100

I = 0.13x

For second account, he interest rate is 6%. The duration is one year.

Let y represent the principal for the second account. Therefore

P = y

T = 1 year

R = 6

Therefore

I = (y × 6 × 1)/100

I = 0.06y

At the end of the first year he had earned $926 in interest. This means that

0.13x + 0.06y = 926 - - - - - - - -2

Substituting x = 9600 - y into equation 2, it becomes

0.13(9600 - y) + 0.06y = 926

1248 - 0.13y + 0.06y = 926

- 0.13y + 0.06y = 926 - 1248

- 0.07y = -322

y = - 322/- 0.07 = 4600

x = 9600 - y

x = 9600 - 4600

x = 5000

8 0

4 years ago