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snow_tiger [21]
3 years ago
8

The surface area of a cone is given by the formula S= nl + ar2 Solve the formula for I.

Mathematics
1 answer:
Drupady [299]3 years ago
3 0
Bbsnsndhvdhdjjdbrhdjdgrgbfhdjixgfhrurhfhrjhfgrjhdbdrh
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Kyra has a rock collection when she puts her rocks into 2 equal piles there are no rocks left over when she puts her rocks into
jeyben [28]
Kyra has 12 rocks in her rock collection.
6 0
3 years ago
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H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.
natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

<h3>Given information-</h3>

The given function is,

h(x)=x^2+1

k(x)=x-2

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

(h+k)(x)=h(x)+k(x)

(h+k)(x)=x^2+1+x-2

(h+k)(2)=2^2+1+2-2

(h+k)(x)=5

2)The value of the function (h-k)(3),

(h-k)(x)=h(x)-k(x)

(h-k)(x)=x^2+1-x+2

(h-k)(3)=3^2+1-3+2

(h-k)(x)=9

3) The value of the function 3h(2)+2k(3)

3h(x)+2k(x)=3x^2+3+2x-2\times 2

3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2

3h(2)+2k(3)=17

Hence the value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

Learn more about the quadratic equation here;

brainly.com/question/2263981

4 0
3 years ago
Explain why you would make one of the addends a tens number when solving an addition problem
leonid [27]
<span> You refer to a multiple of ten. As a multiple of ten you can just add it to another number easier than a "ones number".</span>
4 0
3 years ago
Suppose that G(x) = F(x-6) - 3. Which statement best compares the graph of
aleksklad [387]

Answer:

B

Step-by-step explanation:

Since G(x) =F(x-6)-3

So on the x-axis it will shift - 6 units so to the left and - 3 units on the y-axis then 3 units down.

5 0
4 years ago
Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
lbvjy [14]

Answer:

4.51\times10^{-10}

Step-by-step explanation:

There are only 2 solutions for none of the rooks can capture any of the other rooks: only if they are laid out in either of the 2 diagonal of the chess board

The number of possible combination for the rock to laid out in 8x8 (64 slots) chess board

\frac{64 * 63 * 62 * 61 * 60 * 59 * 58 * 57}{8!} = \frac{1.78\times10^{14}}{40320} = 4426165368 possible combination

So the probability is pretty thin

P = 2 / 4426165368 = 4.51\times10^{-10}

4 0
4 years ago
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