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slamgirl [31]

I will help you with answering this question.

3 0

3 years ago

How many molecules are contained in 103.4g of sulfuric acid?

Ierofanga [76]

<h3>Answer:</h3>

1.827 × 10²⁴ molecules H₂S

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Compounds

Writing Compounds
Acids/Bases

Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

Step 1: Define

103.4 g H₂S (Sulfuric Acid)

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol

Step 3: Convert

Set up: $\displaystyle 103.4 \ g \ H_2S(\frac{1 \ mol \ H_2S}{34.09 \ g \ H_2S})(\frac{6.022 \cdot 10^{23} \ molecules \ H_2S}{1 \ mol \ H_2S})$
Multiply: $\displaystyle 1.82656 \cdot 10^{24} \ molecules \ H_2S$

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

1.82656 × 10²⁴ molecules H₂S ≈ 1.827 × 10²⁴ molecules H₂S

4 0

3 years ago

Would you expect the carbonyl carbon of benzaldehyde to be more or less electrophilic than that of acetaldehyde? Explain using r

Slav-nsk [51]

Answer:

Benzaldehyde is less electrophilic than acetaldehyde

Explanation:

Electrophilicity of carbonyl carbon depends on it's positive charge density.

In benzaldehyde, phenyl group can act as an electron donating group towards carbonyl group due to it's electron donating resonating effect.

In acetaldehyde, methyl group can act as an electron donating group towards carbonyl group due to it's electron donating inductive effect.

We know that resonating effect are more stronger than inductive effect.

Henece, it is expected that positive charge density on carbonyl carbon is much lower in benzaldehyde than acetaldehyde.

So, benzaldehyde is less electrophilic than acetaldehyde.

Resonating effect of phenyl group has been shown below.

4 0

3 years ago

What volume of 0.4567 m h2so4 is required to neutralize 30.00 ml of 0.3210 m naoh?

sertanlavr [38]

Answer is: volume of H₂SO₄ is 42.1 mL.
Chemical reaction: H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.
c(H₂SO₄) = 0,4567 M = 0,4567 mol/L.
V(NaOH) = 30 mL ÷ 1000 mL/L = 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
n(NaOH) = 0,00963 mol.
From chemical reaction: n(H₂SO₄) : n(NaOH) = 1 : 2.
n(H₂SO₄) = 0,01926 mol.
V(H₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).
V(H₂SO₄) = 0,01926 mol ÷ 0,4567 mol/L.
V(H₂SO₄) = 0,0421 L = 42,1 mL.

3 0

3 years ago

Identify the examples of diffusion in the list below. check all that apply

hram777 [196]

Answer: A, B, D

Explanation:

all of these examples show matter moving from a high volume of matter, to low volume of matter. When the molecules of the paint, toast, and chemicals were released, they will try to disperse away from the high concentration

5 0

3 years ago