Will give brainliest

How does the presence of hcl affect the charges on the complexes?

FrozenT [24]

Hydrochloric Acid (HCl) is a strong acid when it is present in the concentrated form but when it is dissolved in water ( $H_2O$ ) the atoms of this compound dissociates into its respective ions as shown below:

$HCl(aq.) + H_2O(aq.) \rightarrow H_3O^+(aq.) + Cl^-(aq.)$

When we add HCl to any complex in its concentrated form the complex does not react at all but when its diluted to 6M and is kept for many hours, the complex reacts slowly. For eg:

$[Co(NH_3)_6]^3^+(aq.) + HCl(aq.) \rightarrow [Co(NH_3)_5Cl]^2^+(aq.) + NH_4^+ (aq.)$

As seen from the above reaction it can be seen the positive charge on the complex is reduced by 1 unit because one $Cl^-$ ion gets attached to the centre metal atom, therefore we can conclude that the charge on complex gets reduced by 1 unit when HCl reacts with the complex.

7 0

3 years ago

What would the mass of 7 red apples be in kilograms?

Bogdan [553]

Answer:

I think it would be at 0.7 kg mass of the sun

8 0

3 years ago

Calculate the molar mass of Fe2(SO4)3. Then Calculate the mass of iron(III) sulfate of 4.05x10^23 formula units. Work must be sh

Talja [164]

Answer:

Molar mass: 399.9 g/mol

The mass of iron(III) sulfate is 269 grams.

Explanation:

First of all, you have to find the molar mass of Fe2(SO4)3.

So you find the molar first for each element

However, there are 2 iron atoms, 3 sulfur atoms, and 12 oxygen atoms.(Don't forget the 3 outside the parenthesis of SO4).

So you do this

So the final answer is 399.9 g/mol

Second of all, if you want to find the mass of Fe2(SO4)3, you have to convert from formula units to moles. After that, then you convert from moles to grams.

If you want to convert from molecules to molecules, you have to use Avogadro's number. Avogadro's number is 6.02 x 10^23. Then if you want to convert from moles to grams, you use the molar mass. We already know that the molar mass is 399.9 g/mol.

Therefore, now use dimensional analysis to show your work.

<h3>(4.05 x 10^23) formula units of Fe2(SO4)3 * 1 mol/ 6.02 x 10^23 formula units * 399.9 g/mol / mol</h3>

Formula units in the beginning and the moles will cancel out.

But we need to use significant figures with the least digits(which is 4.05) So we round to the nearest whole number.

So the final answer for the mass of iron(III) sulfate is 269 grams(don't forget the units).

Hope it helped!

5 0

3 years ago

Help! It’s for chemistry I attached a picture thank you!

IgorLugansk [536]

Answer:

0.15 L

Explanation:

You need to first find the volume of the container. You can do this by dividing the mass by the density. This will give you the mass in mL.

5.00 kg = 5,000 g

(5,000 g)/(1.00 g/mL) = 5,000 mL

5,000 mL = 5 L

Now, find the volume the seawater will take up.

(5,000 g)(1.03 g/mL) = 4854.4 mL

4854.4 mL = 4.85 L

Subtract the two volumes to find the volume that left unfilled.

5 L - 4.85 L = 0.15 L

6 0

3 years ago

In the following reaction 6.13 g of water is actually produced, but the theoretical yield of water is 8.17 g. What is the percen

CaHeK987 [17]

Answer:

75.0%

Explanation:

Data obtained from the question. This includes the following:

Actual yield = 6.13g

Theoretical yield = 8.17g

Percentage yield =...?

The percentage yield can be obtain by using the following formula:

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 6.13/8.17 x 100

Percentage yield = 75.0%

Therefore, the percentage yield of water from the reaction above is 75.0%

3 0

4 years ago