<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
This will be 2400 cause there is nothing in the ones place
Domain: {-4, -2, 0, 2, 4}
range: {-2, -1, 0, 1, 2}
Answer:
C
Step-by-step explanation:
The pool raises 30 inches every 4 secounds
Therefore the equations to find the answer is 30 divided by 4 which equals 7.5
Answer:
x=2
Step-by-step explanation:
This is a one-to-one relationship, so when the output (range) is 4, the input (domain) is 2