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4 years ago

Which container holds the most?

1 answer:

6 0

Cylinder:

V = pi * r^2 * h

V = 3.14 * 9^2 * 11

Simplify exponent:

V = 3.14 * 81 * 11

Multiply:

V = 2797.74

Sphere:

V = 4/3 * pi * r^3

V = 4/3 * 3.14 * 9^3

Simplify exponent:

V = 4/3 * 3.14 * 729

Multiply:

V = 3052.08

Cone:

V = 1/3 * pi * r^2 * h

V = 1/3 * 3.14 * 12^2 * 20

Simplify exponent:

V = 1/3 * 3.14 * 144 * 20

Multiply:

V = 3014.4

So the Sphere holds the most.

You might be interested in

Dorian is spreading mulch on his triangular flowerbed. If the base is 8 feet and the height is 6 feet. How many square feet of m

katovenus [111]

Answer:

24 square feet

Step-by-step explanation:

Given:

Dorian is spreading mulch on his triangular flowerbed.

The base is 8 feet.

The height is 6 feet.

Question asked:

How many square feet of mulch will he need for the flowerbed?

Solution:

The base of triangular flowerbed = 8 feet.

The height of triangular flowerbed = 6 feet.

now, to find how many square feet of mulch he will need for the flowerbed, we will find area of the triangular flowerbed:-

As we know:

$Area\ of\ triangle=\frac{1}{2} \times base\times height$

$=\frac{1}{2} \times8\times6\\\\ =\frac{48}{2} \\ \\ =24\ square\ feet$

Thus, 24 square feet of mulch he will need for the flowerbed.

8 0

3 years ago

Solve each equation. I don't know this

MArishka [77]

1. $(2x - 3)(x + 7) = 0$
 $2x^{2} + 14x - 3x - 21 = 0$
 $2x^{2} + 11x - 21 = 0$

 $x = \frac{-11 +/- \sqrt{11^{2} - 4(2)(-21)}}{2(2)}$

 $x = \frac{-11 +/- \sqrt{121 + 168}}{4}$

 $x = \frac{-11 +/- \sqrt{289}}{4}$

 $x = \frac{-11 +/- 17}{4}$

 $x = -2.75 +/- 4.25$
 $x = -2.75 + 4.25$ $x = -2.75 - 4.25$
 $x = 1.5$ $x = -7$
---------------------------------------------------------------------------------------------------------- 2. $8x(2x - 5) = 0$
 $8x(2x) - 8x(5) = 0$
 $16x^{2} - 40x = 0$
 $16x^{2} - 4x + 0 = 0$

 $x = \frac{-(-40) +/- \sqrt{(-40)^{2} - 4(16)(0)}}{2(16)}$

 $x = \frac{40 +/- \sqrt{1600 - 0}}{32}$

 $x = \frac{40 +/- \sqrt{1600}}{32}$

 $x = \frac{40 +/- 40}{32}$

 $x = 1.25 +/- 1.25$
 $x = 1.25 + 1.25$ $x = 1.25 - 1.25$
 $x = 2.5$ $x = 0$
----------------------------------------------------------------------------------------------------------
3. $x^{2} + 3x - 10 = 0$

 $x = \frac{-3 +/- \sqrt{3^{2} - 4(1)(-10)}}{2(1)}$

 $x = \frac{-3 +/- \sqrt{9 + 40}}{2}$

 $x = \frac{-3 +/- \sqrt{49}}{2}$

 $x = \frac{-3 +/- {7}}{2}$

 $x = -1.5 +/- 3.5$
 $x = -1.5 + 3.5$ $x = -1.5 - 3.5$
 $x = 2$ $x = -5$
----------------------------------------------------------------------------------------------------------
4. $x^{2} = 13x - 36$
 $x^{2} - 13x + 36 = 13x - 13x - 36 + 36$
 $x^{2} - 13x + 36 = 0$

 $x = \frac{-(-13) +/- \sqrt{(-13)^{2} - 4(1)(36)}}{2(1)}$


 $x = \frac{13 +/- \sqrt{169 - 144}}{2}$

 $x = \frac{13 +/- \sqrt{25}}{2}$

 $x = \frac{13 +/- 5}{2}$

 $x = 6.5 +/- 2.5$
 $x = 6.5 + 2.5$ $x = 6.5 - 2.5$
 $x = 9$ $x = 4$
----------------------------------------------------------------------------------------------------------
5. $3x^{2} - 7x + 2 = 0$

 $x = \frac{-(-7) +/- \sqrt{(-7)^{2} - 4(1)(2)}}{2(3)}$

 $x = \frac{7 +/- \sqrt{49 - 8}}{6}$

 $x = \frac{7 +/- \sqrt{41}}{6}$

 $x = \frac{7 +/- 6.403124237432849}{6}$

 $x = 1.167+/- 1.06718737290547$
 $x = 1.67 + 1.06718737290547$ $x = 1.167 - 1.06718737290547$
 $x = 2.73718737290547$ $x = 0.60281262709453$
----------------------------------------------------------------------------------------------------------
6. $10x^{2} - 10x + 9 = 5x^{2} + 4x + 1$
 $10x^{2} - 5x^{2} - 10x + 10x + 9 - 1 = 5x^{2} - 5x^{2} + 4x + 10x + 1 - 1$
 $5x^{2} + 8 = 14x$
 $5x^{2} - 14x + 8 = 14x - 14x$
 $5x^{2} - 14x + 8 = 0$

 $x = \frac{-(-14) + \sqrt{(-14)^{2} - 4(5)(8)}}{2(5)}$

 $x = \frac{14 +/- \sqrt{196 - 160}}{10}$

 $x = \frac{14 +/- \sqrt{36}}{10}$ .

 $x = \frac{14 +/- 6}{10}$

 $x = 1.4 +/- 0.6$
 $x = 1.4 + 0.6$ $x = 1.4 - 0.6$
 $x = 2$ $x = 0.8$

5 0

4 years ago

Select the correct answer. Which statement is correct with respect to f(x) = -3|x − 1| + 12?

professor190 [17]

Answer:

Opt. D.

Step-by-step explanation:

To solve this problem we need to focus our attention in the abs(x-1) function,

If x>1, then abs|x-1|= x-1, if x<1 then abs|x-1|= 1-x. And in the two intervals, the function opens upwards.

But our function has -3 multiplying abs|x-1|, This means that our function opens downward.

The vertex point can be found when x=1, since abs(x-1)=0. this gives f(1)=12

5 0

4 years ago

What is <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bz%E2%81%B4%7D%7Bxyz%7D" id="TexFormula1" title="\frac{z⁴}{xyz}" alt="\frac{z

alexandr1967 [171]

Answer:

The answer would be

$\frac{z {}^{3} }{xy}$

Step-by-step explanation:

the common factor i.e. z gets canceled out

4 0

3 years ago

In the diagram, what is m ASR? MZVSR= RS U Wandern Im

MAVERICK [17]

Answer:

m angle VSR=80°

Step-by-step explanation:

Lines must always be 180° and VSU is already 100° because VSR is supplementary it is 80

5 0

4 years ago