Answer:
Least possible value of b is 9.
Step-by-step explanation:
It is given that 
and b is an odd integer.
We need to find the least possible value of b.
We have,
Isolate variable terms.
Divide both sides by 3.
Since b>8 and b an odd integer, therefore the possible values of b are 9, 11, 13, 15, ... .
Hence, the least possible value of b is 9.
Answer:
−3 < x ≤ 1
Step-by-step explanation:
The domain of a function is the set of x-values.
In this graph, the open circle at (-3, -4) means the segment goes back up to this point but this point is not part of the segment itself.
The closed circle at (1, 2) means this is the endpoint and part of the segment.
This means the x-values range from almost -3 up to and including 1; this gives us the inequality
−3 < x ≤ 1
<h2>Solution :- </h2>
Let the number be "x" , then according to the question :
• 2x - 12 = -8
Further solving
→ 2x = -8 + 12
→ 2x = 4 .
→ x = 2
Answer: The equation of an ellipse:
(
x
−
h
)
2
a
2
+
(
y
−
k
)
2
b
2
=
1
;
a
>
b
Has vertices at
(
h
±
a
,
k
)
Has foci at
(
h
±
√
a
2
−
b
2
,
k
)
Use the vertices to write 3 equations:
k
=
4
[1]
h
−
a
=
−
6
[2]
h
+
a
=
10
[3]
Use equations [2] and [3] to solve for h and a:
2
h
=
4
h
=
2
a
=
8
Use the focus to write another equation:
8
=
h
+
√
a
2
−
b
2
Substitute values for h and a:
8
=
2
+
√
8
2
−
b
2
6
=
√
64
−
b
2
36
=
64
−
b
2
b
2
=
64
−
36
b
2
=
28
b
=
√
28
Substitute the values into the standard form:
(
x
−
2
)
2
8
2
+
(
y
−
4
)
2
(
√
28
)
2
=
1
