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erma4kov [3.2K]
3 years ago
11

Someone assist me please thank you

Mathematics
1 answer:
icang [17]3 years ago
5 0

Answer:

I am pretty sure thats acute triangle but not 100%

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A tourist boat is used for sightseeing in a nearby river. The boat travels 2.4 miles downstream and in the same amount of time,
topjm [15]

Answer: the current of the river is 3 mph.

Step-by-step explanation:

Let x represent the current of the river.

The boat travels 2.4 miles downstream. Assuming it travelled with the current of the river. If the boat travels at an average speed of 21 miles per hour in the still water, it means that the total speed at which the boat travelled downstream is

(21 + x) mph

Time = distance/speed

Time taken to travel downstream is

2.4/(21 + x)

it travels 1.8 miles upstream. Assuming it travelled against the current of the river. it means that the total speed at which the boat travelled upstream is

(21 - x) mph

Time taken to travel upstream is

1.8/(21 - x)

Since the time taken to travel upstream and downstream is the same, then

2.4/(21 + x) = 1.8/(21 - x)

Cross multiplying, it becomes

2.4(21 - x) = 1.8(21 + x)

50.4 - 2.4x = 37.8 + 1.8x

2.4x + 1.8x = 50.4 - 37.8

4.2x = 12.6

x = 12.6/4.2

x = 3 mph

7 0
3 years ago
Read 2 more answers
Which of the following expressions are equivalent
gtnhenbr [62]

Answer:

where's the equations and expressions..?

6 0
4 years ago
Which line segment is a diameter of circle F? <br> FE¯¯¯¯¯ <br> EC¯¯¯¯¯<br> BA¯¯¯¯¯ <br> AC¯¯¯¯¯
netineya [11]
Ac and BE are the diameters of a circle F
diameter passes through the centre
4 0
3 years ago
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1. What is the opposite of -17
djyliett [7]

Answer:

Step-by-step explanation:

17

5 0
3 years ago
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Calcula el radio de un cilindro que tiene 8 cm de altura y un volumen de 122 cm cúbicos
kondaur [170]

Answer:

\huge{ \boxed{ \sf{2.20 \: cm}}}

Step-by-step explanation:

\star{ \sf{ \:  altura  \: de \:  un \:  cilindro\:  =  \: 8 \: cm}}

\star{ \sf{ \: volumen  \: de  \: un  \: cilindro = 122  \: cm \:  cúbicos}} \:

\star {  \sf{ \: encontrar :radio   \: de  \: un  \:  cilindro }}

\boxed{ \sf{ \: Volume \: of \: a \: cylinder \:  =  \:  {\pi \: radius}^{2}  \: height}}

\mapsto{ \sf{122 \:  =  \: ( \frac{22}{7} )r \: ^{2}  \:  \times  \: 8}}

\mapsto{ \sf{122 = 25.14 \:  {r}^{2} }}

\mapsto{ \sf{25.14 \:  {r}^{2} = 122 }}

\mapsto{ \sf{ \frac{25.14 \:  {r}^{2} }{25.14}  =  \frac{122}{25.14}}}

\mapsto{ \sf{ {r}^{2} = 4.85 \: cm}}

\mapsto{ \sf{r = 2.20 \: cm}}

radio de un cilindro = 2.20 cm

\sf{espero  \: haber \:  ayudado!}

\sf{atentamente \:}!

~\sf{TheAnimeGirl}

5 0
3 years ago
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