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2 years ago

Zinc sulfide + magnesium arsenate → zinc arsenate +

Chemistry

1 answer:

Black_prince [1.1K]2 years ago

3 0

The formula equation for the reaction between zinc sulfide and magnesium arsenate is

3ZnS + Mg₃(AsO₄)₂ → Zn₃(AsO₄)₂ + 3MgS

<h3>What is a chemical equation? </h3>

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

<h3>How to write the formula equation </h3>

Zinc sulfide => ZnS

Magnesium arsenate => Mg₃(AsO₄)₂

Zinc arsenate => Zn₃(AsO₄)₂

Magnesium sulfide => MgS

Zinc sulfide + Magnesium arsenate → Zinc arsenate + Magnesium sulfide

3ZnS + Mg₃(AsO₄)₂ → Zn₃(AsO₄)₂ + 3MgS

Learn more about chemical equation:

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1,500 grams is equal to:<br> 1.5 kg<br> 1.5L<br> 1.5 cm<br> all of the above

Salsk061 [2.6K]

1kg is 1,000 grams plus .5 is 1.5 kg

8 0

3 years ago

por favor es urgente!!!!!!!!.... 1 -¿cuántos átomos- gramos de cloro hay en 88,75 g de dicho elemento? 2-¿calcular los moles de

Mamont248 [21]

Answer:

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3 years ago

Identify the reactants and the products in this chemical equation.<br><br> 2Fe2O3 + 3C → 4Fe + 3CO2

aivan3 [116]

Answer:

Fe₂O₃ and C are reactants

Fe and CO₂ are products

Explanation:

Reactants:

Chemical species that are present on left side of chemical reaction equation are called reactants.

Product:

Chemical species that are present on right side of chemical reaction equation are called product.

Chemical equation:

2Fe₂O₃ + 3C → 4Fe + 3CO₂

In this reaction 2 mole of iron oxide is react with three moles of carbon and produced four moles of iron and three moles of carbon dioxide. There are equal numbers of atoms of all elements present on both side of chemical reaction so this reaction follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

7 0

3 years ago

Pentane is a small liquid hydrocarbon, between propane and gasoline in size at C5H12. The density of pentane is 0.626 g/mL and i

Goshia [24]

Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and $3.073\times 10^4kJ/L$ respectively.

Explanation :

Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).

As we are given that:

$\Delta H^o_{comb}=-3535kJ/mol$

Fuel value = $\frac{\Delta H^o_{comb}}{\text{Molar mass of pentane}}$

Molar mass of pentane = 72 g/mol

Fuel value = $\frac{3535kJ/mol}{72g/mol}$

Fuel value = 49.09 kJ/g

Now we have to calculate the fuel density of pentane.

Fuel density = Fuel value × Density

Fuel density = (49.09 kJ/g) × (0.626g/mL)

Fuel density = 30.73 kJ/mL = $3.073\times 10^4kJ/L$

Thus, the fuel density of pentane is $3.073\times 10^4kJ/L$

4 0

4 years ago

Calcule la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) que se preparó al mezclar, en un recipiente aforado, 4 mo

oee [108]

Considerando la definición de molaridad, la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) es 0.5 $\frac{moles}{litro}$ .

La molaridad es una medida de la concentración de un soluto en una disolución que se define como el número de moles de soluto que están disueltos en un determinado volumen.

La molaridad de una solución se calcula dividiendo los moles del soluto por el volumen de la solución:

$Molaridad=\frac{numero de moles de soluto}{volumen}$

La Molaridad se expresa en las unidades $\frac{moles}{litro}$ .

En este caso, sabes que una solución acuosa se preparó al mezclar 4 moles del ácido con suficiente agua hasta completar 8 litros de solución. Entonces, sabes que:

número de moles de soluto= 4 moles
volumen= 8 litros

Reemplazando en la definición de molaridad:

$Molaridad=\frac{4 moles}{8 litros}$

Resolviendo:

Molaridad= 0.5 $\frac{moles}{litro}$

Finalmente, la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) es 0.5 $\frac{moles}{litro}$ .

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3 years ago