All categories

1 year ago

Zinc sulfide + magnesium arsenate → zinc arsenate +

Chemistry

1 answer:

Black_prince [1.1K]1 year ago

3 0

The formula equation for the reaction between zinc sulfide and magnesium arsenate is

3ZnS + Mg₃(AsO₄)₂ → Zn₃(AsO₄)₂ + 3MgS

<h3>What is a chemical equation? </h3>

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

<h3>How to write the formula equation </h3>

Zinc sulfide => ZnS

Magnesium arsenate => Mg₃(AsO₄)₂

Zinc arsenate => Zn₃(AsO₄)₂

Magnesium sulfide => MgS

Zinc sulfide + Magnesium arsenate → Zinc arsenate + Magnesium sulfide

3ZnS + Mg₃(AsO₄)₂ → Zn₃(AsO₄)₂ + 3MgS

Learn more about chemical equation:

brainly.com/question/7181548

You might be interested in

What is the [H ] of a solution of 0.001 M aqueous sulfuric acid (H2SO4) is H2SO4 ionizes in water according to the balanced chem

Ainat [17]

Answer: 0.002 M

Explanation:

The balanced chemical equation for ionization of $H_2SO_4$ in water is:

$H_2SO_4\rightarrow 2H^++SO_4^{2-}$

According to stoichiometry :

1 mole of $H_2SO_4$ ionizes to give =2 mole of $H^+$ ions

0.001 mole of $H_2SO_4$ ionizes to give = $\frac{2}{1}\times 0.001=0.002$ mole of $H^+$ ions

Thus $H^+$ of a solution of 0.001 M aqueous sulfuric acid is 0.002 M

4 0

2 years ago

The density of ethanol is 0.789 g/cm^3 at 20 degrees C. What volume of ethanol has a mass of 15.5 grams?

lys-0071 [83]

<span>density = mass / volume

given the quotient , we have density and mass, volume can be easily calculated as:

volume = mass / p =15.5 g / 0.789 g/cm^3

=~ 20 cm^3 (dimension ally constant)</span>

6 0

3 years ago

Which pair shares the same empirical formula?

ZanzabumX [31]

Answer:- 3. $CH_3$ and $C_2H_6$

Explanations:- An empirical formula is the simplest whole number ratio of atoms of each element present in the molecule/compound.

For example, the molecular formula of benzene is $C_6H_6$ . The ratio of C to H in it is 6:6 that could be simplified to 1:1. So, an empirical formula of benzene is CH.

In the first pair, the ratio of C to H in first molecule is 2:4 that could be simplified to 1:2 and the empirical formula is $CH_2$ . In second molecule the ratio of C to H is 6:6 and it could be simplified to 1:1. and the empirical formula is CH. Empirical formulas are different for both the molecules of first pair and so it is not the right choice.

In second pair, C to H ratio in first molecule is 1:2, so the empirical formula is $CH_2$ . The C to H ratio for second molecule is 1:4, so the empirical formula is $CH_4$ . Here also, the empirical formulas are not same and hence it is also not the right choice.

In third pair, C to H ratio in first molecule is 1:3, so the empirical formula is $CH_3$ . In second molecule the C to H ratio is 2:6 and it is simplified to 1:3. So, the empirical formula for this one is also $CH_3$ . Hence. this is the correct choice.

In fourth pair, first molecule empirical formula is CH. Second molecule has 2:4 that is 1:2 mole ratio of C to H and so its empirical formula is $CH_2$ . As the empirical formulas are different, it is not the right choice.

So, the only and only correct pair is the third one. 3. $CH_3$ and $C_2H_6$

4 0

3 years ago

Read 2 more answers

Consider the following system at equilibrium:

Vika [28.1K]

Answer:

1) Rightward shift

2) Rightward shift

3) Leftward shift

4) Leftward shift

5) Leftward shift

6) Rightward shift

7) No shift

8) No shift

Explanation:

To evaluate each case we need to consider Le Chatelier's Principle, which states that the adding of additional reactants or products to a system will shift the equilibrium in the opposite direction, to maintain the equilibrium of the system. On the contrary, if we remove a reactant or a product in the system, the equilibrium will be shifted in the direction of the reactant or product reduced, to produce more of it (and thus maintain balance).

Taking into account the above, let's see each statement, in the following equation:

A(aq) + B(aq) ⇄ 2C(aq) (1)

1) Increase A. This will cause a rightward shift in equation 1 in order to consume the reactant added.

2) Increase B. Same as 1), this will cause a rightward in equation 1.

3) Increase C. This will cause a leftward shift in order to consume the excess of product in the system.

4) Decrease A. This will produce a leftward shift to produce the reactant that is being reduced.

5) Decrease B. Same as 4), a leftward shift.

6) Decrease C. This will produce a rightward shift to produce the product that is being reduced.

7) Double A, half B. The double A will cause a rightward shift and the half B will produce a leftward shift, which results in no shift.

8) Double both B and C. Double B will produce a rightward shift and double C will produce the contrary, a leftward shift, so the final result is no shift.

I hope it helps you!

4 0

3 years ago

What are some chemical changes in oxygen?

Zinaida [17]

the oxidation reaction between oxygen and sodium produces sodium oxide. In many cases, an element may form more than one oxide.

Explanation:

4 0

2 years ago