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Katyanochek1 [597]
1 year ago
9

Zinc sulfide + magnesium arsenate → zinc arsenate +

Chemistry
1 answer:
Black_prince [1.1K]1 year ago
3 0

The formula equation for the reaction between zinc sulfide and magnesium arsenate is

3ZnS + Mg₃(AsO₄)₂ → Zn₃(AsO₄)₂ + 3MgS

<h3>What is a chemical equation? </h3>

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

<h3>How to write the formula equation </h3>

Zinc sulfide => ZnS

Magnesium arsenate => Mg₃(AsO₄)₂

Zinc arsenate => Zn₃(AsO₄)₂

Magnesium sulfide => MgS

Zinc sulfide + Magnesium arsenate → Zinc arsenate + Magnesium sulfide

3ZnS + Mg₃(AsO₄)₂ → Zn₃(AsO₄)₂ + 3MgS

Learn more about chemical equation:

brainly.com/question/7181548

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A chemist determines by measurements that moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrog
Likurg_2 [28]

Answer:

0.56 g

Explanation:

<em>A chemist determines by measurements that 0.020 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrogen gas that participates.</em>

Step 1: Given data

Moles of nitrogen gas (n): 0.020 mol

Step 2: Calculate the molar mass (M) of nitrogen gas

Molecular nitrogen is a gas formed by diatomic molecules, whose chemical formula is N₂. Its molar mass is:

M(N₂) = 2 × M(N) = 2 × 14.01 g/mol = 28.02 g/mol

Step 3: Calculate the mass (m) corresponding to 0 0.020 moles of nitrogen gas

We will use the following expression.

m = n × M

m = 0.020 mol × 28.02 g/mol

m = 0.56 g

4 0
3 years ago
How to do Lewis structure for Al?
Gnoma [55]

Notes:-

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electron configuration:-

  • [Ne]3s²3p³

Valency is 3

So 3 dots are included

4 0
2 years ago
Need asap! Step-by-step pls: Determine the empirical formula: 32.37% Na, 22.58% S, 45.05% O​
Ludmilka [50]

1) divide each percentage by the relative atomic mass of the element

2) divide all results by the smallest number

3)multiply by a whole number to get the simplest whole number ratio (if necessary)

that is to say:

Na                                   S                            O

32.37÷23                 22.58÷32                45.05÷16

= 1.407                       = 0.7056               = 2.816       (to 4 significant figures)

the smallest number here is 0.7056 so:

1.407÷0.7056        0.7056÷0.7056       2.816÷0.7056

=1.99 approx.2                   = 1                   3.99 approx. 4

here there is no need to carry out step 3 as ratio obtained is already a simplest whole number  ratio

so empirical formula is: Na₂SO₄

8 0
3 years ago
Which equation represents a transuranium​
Maksim231197 [3]

Answer:

1) Since you have not provided the equations to select the right one, I am going to explain you the relevant facts that are used to solve this question.

2) The transuranium elements are the chemiical elements with atomic number greater than that of the uranium.

The atomic number of uranium is 92. So, the transuranium elements are the elements with atomic number 93 or greater.

This are some of the transuranium elements:

Neptunio - 93

Plutonium - 94

Americium - 95

Curium - 96

Berkelium - 97

Californium - 98

Einstenium - 99

And so all the known elements (the last one is the 118).

3) In a nuclear reaction the total mass number ( shown as superscript to the left of the symbol) and total atomic number (shown as subscript to the left of the symbol) are conserved.

4) Beta decay is the release of a beta particle, which is an electron (considered massles and with charge - 1). So, the beta decay is represented with the symbol:

0

 β, which means 0 mass and charge - 1.

-1

5) This is, then, an example of a β decay equation for one transuranium element:

239              239            0

     Np    →         Pu   +      β

 93                94            -1

As you see 239 = 239 + 0 and 93 = 94 - 1, showing that the total mass number ( shown as superscript to the left of the symbol) and the total atomic number (shown as subscript to the left of the symbol) are conserved.

Explanation:

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Which of the following is an example of chemical weathering?
REY [17]

Answer:

the answer is C acid dissolving limestone

Explanation:

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