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Serggg [28]
3 years ago
6

Which of the following would dissolve in water? CCl4 LiCl CH4 PCl6

Chemistry
2 answers:
babymother [125]3 years ago
7 0
Like dissolves like
so water is polar

CCl4 is nonpolar
LiCl is polar
CH4 is nonpolar
PCl6 is nonpolar

so LiCl would dissolve
kupik [55]3 years ago
7 0

Answer: LiCI

Explanation:

Water dissolves polar and ionic substances. The other three options are non-polar.

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1: Write balanced complete ionic equation for
monitta

Answer 1 : The balanced complete ionic equation will be,

NaOH(aq)+HNO_3(aq)\rightarrow H_2O(l)+NaNO_3(aq)

Na^+(aq)+OH^-(aq)+H^+(aq)+NO_3^-(aq)\rightarrow H_2O(l)+Na^+(aq)+NO_3^-(aq)

By removing the spectator ion in this equation, we get the balanced ionic equation.

OH^-(aq)+H^+(aq)\rightarrow H_2O(l)

Answer 2 : The balanced net ionic equation will be,

2Na_3PO_4(aq)+3NiCl_2(aq)\rightarrow Ni_3(PO_4)_2(s)+6NaCl(aq)

6Na^+(aq)+2PO_4^{3-}(aq)+3Ni^+(aq)+6Cl^-(aq)\rightarrow Ni_3(PO_4)_2(s)+6Na^+(aq)+6Cl^-(aq)

By removing the spectator ion in this equation, we get the balanced ionic equation.

2PO_4^{3-}(aq)+3Ni^+(aq)\rightarrow Ni_3(PO_4)_2(s)

Answer 3 : The balanced net ionic equation will be,

2Na_3PO_4(aq)+3NiCl_2(aq)\rightarrow Ni_3(PO_4)_2(s)+6NaCl(aq)

6Na^+(aq)+2PO_4^{3-}(aq)+3Ni^+(aq)+6Cl^-(aq)\rightarrow Ni_3(PO_4)_2(s)+6Na^+(aq)+6Cl^-(aq)

By removing the spectator ion in this equation, we get the balanced ionic equation.

2PO_4^{3-}(aq)+3Ni^+(aq)\rightarrow Ni_3(PO_4)_2(s)

Balanced equations : Balanced equations are the equations in which the number of individual elements present on the reactant side must be equal to the number of individual elements present on the product side.

Spectator ions : It is defined as the ions which do not participate in the chemical reaction. These ions exists in the same form on both the sides of the reaction.

7 0
3 years ago
Read 2 more answers
A 52.0 mL portion of a 1.20 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by a
RoseWind [281]

Answer:

C_3=0.125M

Explanation:

Hello!

In this case, we can divide the problem in two steps:

1. Dilution to 278 mL: here, the initial concentration and volume are 1.20 M and 52.0 mL respectively, and a final volume of 278 mL, it means that the moles remain the same so we can write:

V_1C_1=V_2C_2

So we solve for C2:

C_2=\frac{C_1V_1}{V_2}=\frac{52.0mL*1.20M}{278mL}\\\\C_2=0.224M

2. Now, since 111 mL of water is added, we compute the final volume, V3:

V_3=139+111=250mL

So, the final concentration of the 139 mL portion is:

C_3=\frac{139 mL*0.224M}{250mL}\\\\C_3=0.125M

Best regards!

8 0
3 years ago
What best describes the heat transfer when kinetic energy is converted into potential energy?
Masteriza [31]

Answer:

neither of them, kinetic energy is energy in motion and potential is stored energy so its like saying the heat transfer stopped in a pot

i dont know if that made sense XD

~batmans wife dun dun dun...

4 0
4 years ago
What is the engine piston displacement in liters of an engine who’s displacement is listed as 430 in.²
sergeinik [125]

For an engine whose displacement is listed as 430 in.², the engine piston displacement in liters is mathematically given as

PD= 7.37 L  

<h3>What is the engine piston displacement in liters of an engine whose displacement is listed as 430 in.²?</h3>

Generally, the equation for the dimensional analysis method,\, we convert in to L is mathematically given as

l*(v/l)*l/v

Therefore,  piston displacement

PD=(450 in3) . (1 dm3 / 61.024 in3) . (1 L / 1 dm3)

PD= 7.37 L  

In conclusion, piston displacement

PD= 7.37 L  

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3 years ago
Calculate the weighted average
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