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Serggg [28]
3 years ago
6

Which of the following would dissolve in water? CCl4 LiCl CH4 PCl6

Chemistry
2 answers:
babymother [125]3 years ago
7 0
Like dissolves like
so water is polar

CCl4 is nonpolar
LiCl is polar
CH4 is nonpolar
PCl6 is nonpolar

so LiCl would dissolve
kupik [55]3 years ago
7 0

Answer: LiCI

Explanation:

Water dissolves polar and ionic substances. The other three options are non-polar.

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Animal cells each have a centrosome and lysosomes, whereas plant cells do not. Plant cells have a cell wall, chloroplasts and other specialized plastids, and a large central vacuole, whereas animal cells do not.

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Science / which phrase describes the differences between these two liquid ?
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Explanation:

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3 years ago
In an electrically heated boiler, water is boiled at 140°C by a 90 cm long, 8 mm diameter horizontal heating element immersed in
RideAnS [48]

Explanation:

The given data is as follows.

Volume of water = 0.25 m^{3}

Density of water = 1000 kg/m^{3}

Therefore,  mass of water = Density × Volume

                       = 1000 kg/m^{3} \times 0.25 m^{3}

                       = 250 kg  

Initial Temperature of water (T_{1}) = 20^{o}C

Final temperature of water = 140^{o}C

Heat of vaporization of water (dH_{v}) at 140^{o}C  is 2133 kJ/kg

Specific heat capacity of water = 4.184 kJ/kg/K

As 25% of water got evaporated at its boiling point (140^{o}C) in 60 min.

Therefore, amount of water evaporated = 0.25 × 250 (kg) = 62.5 kg

Heat required to evaporate = Amount of water evapotaed × Heat of vaporization

                           = 62.5 (kg) × 2133 (kJ/kg)

                           = 133.3 \times 10^{3} kJ

All this heat was supplied in 60 min = 60(min)  × 60(sec/min) = 3600 sec

Therefore, heat supplied per unit time = Heat required/time = \frac{133.3 \times 10^{3}kJ}{3600 s} = 37 kJ/s or kW

The power rating of electric heating element is 37 kW.

Hence, heat required to raise the temperature from 20^{o}C to 140^{o}C of 250 kg of water = Mass of water × specific heat capacity × (140 - 20)

                      = 250 (kg) × 40184 (kJ/kg/K) × (140 - 20) (K)

                     = 125520 kJ  

Time required = Heat required / Power rating

                       = \frac{125520}{37}

                       = 3392 sec

Time required to raise the temperature from 20^{o}C to 140^{o}C of 0.25 m^{3} water is calculated as follows.

                    \frac{3392 sec}{60 sec/min}

                     = 56 min

Thus, we can conclude that the time required to raise the temperature is 56 min.

4 0
3 years ago
Which physical property can NOT be observed using 5 senses without changing the chemical makeup of the object that you are obser
bonufazy [111]
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Hydrolamine ,NH2OH , is a reducing agent found in some film developing solutions. How many hydrogen atoms are in 1.80moles of hy
kolezko [41]

Answer:

number of hydrogen atom in 1.8 mole of NH2OH = 9.8\times 10^{22}

Explanation:

percentage of hydrogen in NH2OH = mass of hydrogen / mass of whole molecule

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                                                             = 9.09 percentage

therefore number of moles in 1.8 moles of hydroxy amine = \frac{9.09}{100}\times 1.8

                                                                = .16 moles of hydrogen

number of hydrogen atom = (number of moles )×(avagadro number)

                                              = 9.8\times 10^{22} atoms of hydrogen

3 0
3 years ago
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