The area of the circle A and B is 86.54 inches and 124.62 mm
According to the statement
we have given that the radius of the circle A and b and we have to find the area of the given circle.
So, we know that the
The area enclosed by a circle of radius r is πr².
So, For area of the circle
For condition A :
diameter = 10.5 inches
then radius = 5.25
Area = πr²
Area = 3.14*27.56
Area = 86.54 inches
Now, For condition B :
radius = 6.3 mm
Area = πr²
Area = 3.14*39.69
Area = 124.62mm
So, The area of the circle A and B is 86.54 inches and 124.62 mm
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Answer
i don't think people wanna do it
Step-by-step explanation:
Degree of the Term is the sum of the exponents of the variables. 2x 4y 3 4 + 3 = 7 7 is the degree of the term. 5x-2y 5 NOT A TERM because it has a negative exponent. 8 If a term consists only of a non-zero number (known as a constant term) its degree is 0. Your welcome!
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = $5
For the alternative hypothesis,
µ < $5
number of samples taken = 10
Sample mean, x = (4 + 3 + 2 + 3 + 1 + 7 + 2 + 1 + 1 + 2)/10 = 2.6
To determine sample standard deviation, s
s = √(summation(x - mean)/n
n = 12
Summation(x - mean) = (4 - 2.6)^2 + (3 - 2.6)^2 + (2 - 2.6)^2 + (3 - 2.6)^2 + (1 - 2.6)^2 + (7 - 2.6)^2 + (2 - 2.6)^2 + (1 - 2.6)^2 + (1 - 2.6)^2 + (2 - 2.6)^2 = 30.4
s = √30.4/10 = 1.74
Since the number of samples is 10 and no population standard deviation is given, the distribution is a student's t.
Since n = 10,
Degrees of freedom, df = n - 1 = 10 - 1 = 9
t = (x - µ)/(s/√n)
Where
x = sample mean = 2.6
µ = population mean = 5
s = samples standard deviation = 1.74
t = (2.6 - 5)/(1.74/√10) = - 4.36
We would determine the p value at alpha = 0.05. using the t test calculator. It becomes
p = 0.000912
A 270° counterclockwise rotation leads to this transformation:
(x,y) → (y, - x)
So, we have
original point new point
J (-6,2) → J' (2,6)
K (-4,6) → K' (6,4)
L (-3,3) → L' (3,3)
M (-5,-1) → M' (-1,5)
So, you have the points J', K', L', and M' that define the new parallelogram.
Answer: The coordinates of the endpoints of the side congruent to side KL are the coordinates of K' and L' which are (6,4) and (3,3).
