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alexandr402 [8]
2 years ago
5

Click on the greatest amount of rainfall.

Mathematics
2 answers:
aliya0001 [1]2 years ago
8 0

Answer:

2 posposoospsoskwnahhnaq

hope its help

mixer [17]2 years ago
6 0

Answer:

Click on the 2

Step-by-step explanation:

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How do you solve for x? -10 - 2x > 54
expeople1 [14]

Answer:

x< -64

Step-by-step explanation:

hope this helps ;)

4 0
2 years ago
Read 2 more answers
One of the factors of 34 is chosen at random. What is the probability that the factor is itself a two digit number?
solong [7]
A factor of 30 is chosen at random. What is the probability, as a decimal, that it is a 2-digit number?

The positive whole-number factors of 30 are:

1, 2, 3, 5, 6, 10, 15 and 30.

So, there are 8 of them. Of these, 3 have two digits. Writing each factor on a slip of paper, then putting the slips into a hat, and finally choosing one without looking, get that

P(factor of 30 chosen is a 2-digit number) = number of two-digit factors ÷ number of factors

=38=3×.125=.375
8 0
2 years ago
The numbers 1 to 12 must be placed in the circles of the star shown on the right. The sums of the numbers in each row, and the s
gulaghasi [49]

Answer:

The numbers 1 to 12 must be placed in the circles of the star shown on the right. The sums of the numbers in each row, and the sum of the numbers in the six outer circles of the star, must be equal to 26. Arrange the numbers accordingly.

4 0
1 year ago
Tbh I'm just too lazy to actually do this and my head hurts from the rest of my school work so I'm just asking it on here -2/5 +
Leto [7]

Answer:

1/10

Step-by-step explanation:

-2/5 + 1/2

-4/10 + 5/10

-4 + 5/10

= 1/10

Hope this helps!

6 0
3 years ago
Read 2 more answers
A candy company claims that 20% of the candies in its bags are colored green. Steve buys 30 bags of 30 candies, randomly selects
Allisa [31]

Answer:

The probability of Steve agreeing with the company’s claim is 0.50502.

Step-by-step explanation:

Let <em>X</em> denote the number of green candies.

The probability of green candies is, <em>p</em> = 0.20.

Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.

So, <em>n</em> = 30 candies are randomly selected.

All the candies are independent of each other.

The random variable <em>X</em> follows a binomial distribution with parameter <em>n</em> = 30 and <em>p</em> = 0.20.

It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.

Compute the probability of 5, 6 and 7 green candies as follows:

P(X=5)={30\choose 5}(0.20)^{5}(1-0.20)^{30-5}=0.17228\\\\P(X=6)={30\choose 6}(0.20)^{6}(1-0.20)^{30-6}=0.17946\\\\P(X=7)={30\choose 7}(0.20)^{7}(1-0.20)^{30-7}=0.15328

Then the probability of Steve agreeing with the company’s claim is:

P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)

                                       = 0.17228 + 0.17946 + 0.15328

                                       = 0.50502

Thus, the probability of Steve agreeing with the company’s claim is 0.50502.

7 0
3 years ago
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