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Nataly_w [17]
2 years ago
10

Can someone please help me with this please ASAPPP

Mathematics
1 answer:
Maru [420]2 years ago
8 0

Answer:

a) y= -18x +486

b)

10, y= 306

11, y= 288

12, y= 270

13, y= 252

14, y= 234

15, y= 216

Step-by-step explanation:

I hope this helped! brainliest pls?

<3

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Helpppppp me pleaseeeeeee!!!!!!!!
Nimfa-mama [501]

Answer:

Step-by-step explanation:

think of the flight of a small rocket..  what does it seem like the parabola would look like?  down means it looks like a cup or glass , upside down , up mean a cup or glass right side up.

when t = 0  the rocket is at 25, so that's the initial height

it's velocity is initially 200 m/s

put equation from std. form to vertex form

y = ax^{2} + bx +c       =>       y = a(x - h ) ^2 + k

h = -4.9t^{2} + 200t + 25  =>h = -4.9(t - 20.41)^2 + 2,065.82

(h,k) =  (20.41 , 2065.82)

3 0
3 years ago
Write an equation to represent the following statement.<br> 24 is 4 times as great as k.
Artyom0805 [142]

Answer:

24 x 4 = k x 4

Step-by-step explanation:

8 0
3 years ago
HEY YOU!! PLEASE I NEED HELPPP<br><br> find angle BAC and angle FAB
serious [3.7K]

Answer:

m∠BAC = 105°

m∠FAB = 75°

Step-by-step explanation:

By using the property of an exterior angle of a triangle,

Measure of an exterior angle is equal to the sum of opposite two angles of a triangle.

From the triangle given in the picture,

m∠ABC + m∠BCA + m∠CAB = 180°

(13x - 3)° = (3x + 2)° + 55°

13x - 3 = 3x + 57

13x - 3x = 57 + 3

10x = 60

x = 6

m∠FAB = (13x - 3)° = 75°

m∠ABC = (3x + 2)° = 20°

Since, ∠BAC and ∠FAB are the linear pair of angles,

m∠BAC + m∠FAB = 180°

m∠BAC + 75° = 180°

m∠BAC = 180° - 75° = 105°

8 0
3 years ago
The perimeter of a rectangular field is 324 yards. If the width of the field is 76 yards, what is its length?
Ugo [173]

The length would be 86 yards.

8 0
3 years ago
find the component equation of the plane which is normal to the vector -2i+5j+k and which contains the point (-10;7;5).​
maksim [4K]

Given:

A plane is normal to the vector = -2i+5j+k

It contains the point (-10,7,5).​

To find:

The component equation of the plane.

Solution:

The equation of plane is

a(x-x_0)+b(y-y_0)+c(z-z_0)=0

Where, (x_0,y_0,z_0) is the point on the plane and \left< a,b,c\right> is normal vector.

Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is

-2(x-(-10))+5(y-7)+1(z-5)=0

-2(x+10)+5y-35+z-5=0

-2x-20+5y-35+z-5=0

-2x+5y+z-60=0

-2x+5y+z=60

Therefore, the equation of the plane is -2x+5y+z=60.

4 0
2 years ago
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