The coefficient of the x-term is -3. Add the square of half of that.
.. (-3/2)² = 9/4 . . . . . . the number you need to add.
x² -3x +9/4 = (x -3/2)²
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If the x² term has a coefficient other than 1, you need to factor that out first and deal with the remaining binomial. For example,
.. 2x² -6x = 2(x² -3x)
For this you would need to add 9/4 inside parentheses to get
.. 2(x² -3x +9/4) = 2(x -3/2)²
Of course, to keep the original value, you would need to subtract 2*(9/4) outside parentheses.
.. 2x² -6x = 2(x -3/2)² -9/2
If I’m not mistaken, I believe that it is 4:12
Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
Answer:
They are both proportional.
Tank A = .00375 minutes/gallon
Tank B = 2/600 or ~0.003 minutes/gallon
Step-by-step explanation:
They are both proportional because as time increases, the amount of gallons increases.
Tank A unit rate
Tank B unit rate
Rate = rise / run
Choose points on the graph that has definite points.
Tank A = (1.5 mins - 0.75 mins) / 200 gallons
Tank A = .00375 minutes/gallon
Tank B = (2 mins - 0 mins) / 600 gallons
Tank B = 2/600 or .003 minutes/gallon
Answer:
And we can use the probability mass function and we got:
And replacing we got:
Step-by-step explanation:
Let X the random variable of interest "number of graduates who enroll in college", on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
We want to find the following probability:
And we can use the complement rule and we got:
And we can use the probability mass function and we got:
And replacing we got:
