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Kitty [74]
3 years ago
7

What periodic table element has Atomic Number Z of 79 and neutron of 118?

Chemistry
2 answers:
Ronch [10]3 years ago
5 0

Gold has atomic number 79 and 118 neutrons (mass number-atomic number)

malfutka [58]3 years ago
3 0

Answer:

gold(AU)

Explanation:

hope this helps

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Our current model of a chemical bond is to think of it as an electrical interaction between what two parts of an atom
Nikitich [7]

Answer:

Explanation:

It involves the thinking of it as an electrical interaction between the positively charged part of an atom and the negatively charged part as well. Succinctly put, the interaction between the proton of an atom and the electron of an atom.

The relationship between these two sub atomic particles is one of the basis for many chemical bonding, and this is inclusive of all the bonds there exist. Hydrogen, Electrovalent and even Covalent bondings to mention but a few

5 0
3 years ago
What is the chemistry of super glue
likoan [24]

cyanoacrylate

When cyanoacrylate polymerizes, the cyanoacrylate sticks together on an atomic level, and it becomes solid. Super Glue solidifies in all the microscopic crevices of an object that it moved into when it was a liquid, and it can form chemical bonds with any anions in the object.

5 0
2 years ago
what is the theoretical mass of xenon tetrafluoride that should form when 130.g of xenon is reacted with 100.g of F2? what is th
serg [7]

Answer:

The answer to your question is: 70.7 %

Explanation:

Equation

                  Xe   +   2F₂    ⇒    XeF₄

limiting reactant = Xe

Xe is the limiting reactant because the ratio is:

theoretical = 131/ 76 = 1.72 g

experimental ratio = 130/100 = 1.3  the amount of F increased.

                     131.3 g of Xe ------------------ 207 g of XeF₄

                     130 g of Xe  -------------------  x

                         x = (130 x 207) / 131.3

                        x = 205 g of XeF₄

% yield = 145 / 205 x 100

% yield = 70.7

5 0
3 years ago
What mass, in grams, of aluminum hydroxide will be required to prepare the 4 L of a 1.75 M solution?
brilliants [131]

Answer: 0.53g

Explanation:

No of moles= volume ×molarity/1000

We have the volume and the molarity

Volume=4L

Molarity=1.7M

No of moles = 4×1.7/1000

No of moles= 0.0068moles

Remember also that

No of moles= mass given/molar mass

Molar mass of Al(OH)3

Al= 27

O=16

H=1

Molar mass = Al+(O+H)3

Molar mass= 27+(16+1)3

Molar mass= 27+(17)3

Molar mass = 27+51

Molar mass= 78g/mol

To get the mass

Mass given = no of moles × molar mass

Mass= 0.0068×78

Mass= 0.53g

6 0
4 years ago
In this equation, what should be the coefficients of the reactants and products? I2 + O2 → I4O9
denpristay [2]
4I₂+9O₂= 2I₄+2O₉
Reactants: 8 iodine, 18 oxygen
Products: 8 iodine, 18 oxygen
Balanced!!
3 0
3 years ago
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