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SpyIntel [72]
3 years ago
6

When unbalanced forces act on an object that is in motion, the object can:

Chemistry
1 answer:
AlekseyPX3 years ago
5 0

Answer:

A. change speed, direction, or both

Explanation:

hope this helps. . . <3

good luck!      uwu

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How might the geometry of the product change (oh in an endo or exo position?) if all the methyl groups of camphor were replaced
Greeley [361]

Replacement of methyl groups of camphor is a reduction mechanism. Camphor is a bridged bi-cyclic compound. If you observe the structure of camphor the methyl group is placed with one carbon bridge (7, 7) and two carbon bridge (1). Attack from face of one carbon bridge is termed as exo attack whereas from face of two carbon bridge is termed as endo attack. So replacement will lead to mix of both and formation of two stereo isomers.

Reduction mechanism is often shown with a U-shaped arrow pointing the attack by ion such as in nucleophilic addition reaction.

6 0
3 years ago
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What is made of only one type of atom?
WARRIOR [948]
Hi LianYuLife

Element is a substance that is made up of only one kind of atom

Answer: C) or the third option.
4 0
4 years ago
Read 2 more answers
Newtons second law of motion states that
insens350 [35]

Answer:

The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force,

Explanation:

3 0
3 years ago
Which half-reaction correctly represents reduction?
Gemiola [76]
Answer choice C. Reduction has its electrons as a reactant.
6 0
3 years ago
How many moles are equal to 12.65 grams of Al2(SO4)3?
____ [38]

Answer:

0.03697 mol Al₂(SO₄)₃

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

12.65 g Al₂(SO₄)₃

<u>Step 2: Identify Conversions</u>

Molar Mass of Al - 26.98 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Al₂(SO₄)₃ - 2(26.98) + 3(32.07) + 12(16.00) = 342.17 g/mol

<u>Step 3: Convert</u>

<u />12.65 \ g \ Al_2(SO_4)_3(\frac{1 \ mol \ Al_2(SO_4)_3}{342.17 \ g \ Al_2(SO_4)_3} ) = 0.03697 mol Al₂(SO₄)₃

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

We already have 4 sig figs in the final answer, so no need to round.

5 0
3 years ago
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