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Tatiana [17]
2 years ago
12

What do you have to do to this fraction before we can at the numerators ? 1/4 + 2/7​

Mathematics
1 answer:
motikmotik2 years ago
5 0

Answer:

you have to convert them to equivalent units (the same denominators)

Step-by-step explanation:

first, multiply  2 and 7 by 4.

now you have 8/21.

then, make the other fraction the same value.

multiply 1 and 4 by 7.

7/21.

now your equation is 7/21 + 8/21= 15/21.

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3 dollars for each can of tuna

Step-by-step explanation:

9-3=6

6-3=3

3-3=0

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3 years ago
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In ΔRST, r = 40 cm, s = 88 cm and t=70 cm. Find the measure of ∠S to the nearest degree.
sdas [7]

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102.835≈103

Step-by-step explanation:

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Write the next three numbers in the three numbers in the sequence:0.4, 1.2, 3.6, 10.8
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The rule is 3x
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4 7/12 divided by 3/4 multipled by 3/11
Vlada [557]
Here is the answer With working

6 0
3 years ago
Simplify
Diano4ka-milaya [45]

Answer:

\huge\boxed{\sqrt[4]{16a^{-12}}=2a^{-3}=\dfrac{2}{a^3}}

Step-by-step explanation:

16=2^4\\\\a^{-12}=a^{(-3)(4)}=\left(a^{-3}\right)^4\qquad\text{used}\ (a^n)^m=a^{nm}\\\\\sqrt[4]{16a^{-12}}=\bigg(16a^{-12}\bigg)^\frac{1}{4}\qquad\text{used}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\bigg(2^4(a^{-3})^4\bigg)^\frac{1}{4}\qquad\text{use}\ (ab)^n=a^nb^n\\\\=\bigg(2^4\bigg)^\frac{1}{4}\bigg[(a^{-3})^4\bigg]^\frac{1}{4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=2^{(4)(\frac{1}{4})}(a^{-3})^{(4)(\frac{1}{4})}=2^1(a^{-3})^1=2a^{-3}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}

=2\left(\dfrac{1}{a^3}\right)=\dfrac{2}{a^3}

5 0
3 years ago
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