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Kipish [7]
2 years ago
7

In the given figure find the value of the unknown interior angle x in the following figure.​

Mathematics
1 answer:
Leto [7]2 years ago
5 0

Answer:

Therefore, the measure of angles x is 55°.

Step-by-step explanation:

From the given figure ,

105° is the exterior angle

x° and 50° are the two interior opposite angles to 105°

We know that

An exterior angle formed by extending the side of a triangle is equal to the sum of the two interior opposite angles

⇛ x° + 50° = 105°

⇛ x° = 105°-50°

⇛ x° = 55°

Therefore , x = 55°

<u>Exterior</u><u> </u><u>Angle:</u><u>↓</u>

An exterior angle formed by extending the side of a triangle is equal to the sum of the two interior opposite angles.

Hope this helps!!

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the length of a rectangle is 8 less than twice the width. the perimeter is 38 feet. Find the length and width. someone please he
Aleksandr-060686 [28]

Answer:L=4 W=15

Step-by-step explanation:

P=2L+2W

38-8=30

If length is 8 less than twice the width and the perimeter is 38, then subtract 38-8 which is 30, then divide 30 by 2 to get 15.

P=2(4) +2(15)

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3 years ago
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s
Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that \mu = 1262, \sigma = 118

a) Determine the 26th percentile for the number of chocolate chips in a bag. ​

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

Z = \frac{X - \mu}{\sigma}

-0.643 = \frac{X - 1262}{118}

X - 1262 = -0.643*118

X = 1186

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 1262}{118}

X - 1262 = -1.96*118

X = 1031

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 1262}{118}

X - 1262 = 1.96*118

X = 1493

Between 1031 and 1493.

​(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip​ cookies?

Difference between the 75th percentile and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 1262}{118}

X - 1262 = -0.675*118

X = 1182

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 1262}{118}

X - 1262 = 0.675*118

X = 1342

IQR:

1342 - 1182 = 160

7 0
3 years ago
Label the place value
e-lub [12.9K]
987,164.302
0: hundredths
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4 0
3 years ago
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xxTIMURxx [149]
  • Answer:

<em>(2a - 3x - 3y)(2a + 3x + 3y)</em>

  • Step-by-step explanation:

<em>Hi there !</em>

use formula

<em>a</em><em>² - </em><em>b</em><em>² = (a - b)(a + b)</em>

<em>a</em><em> = 2a</em>

<em>b</em><em> = 3(x + y)</em>

<em />

<em>4a² - 9(x+y)² =</em>

<em>= [2a - 3(x + y)][2a + 3(x + y)]</em>

<em>= (2a - 3x - 3y)(2a + 3x + 3y)</em>

<em />

<em>Good luck !</em>

5 0
3 years ago
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