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3 years ago

Which 3 things are always equal for an atom?

Chemistry

1 answer:

bagirrra123 [75]3 years ago

4 0

Answer:

Atoms always have an equal number of protons and electrons, and the number of protons and neutrons is usually the same as well.

Explanation:

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40 liters is equal to?<br> A. 40 cm3<br> B. 40 m3<br> C. 4,000 ml

9966 [12]

B I think sorry if I’m wrong

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3 years ago

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Help! Pls tell me the meanings of all of these words and please try to make them short as possible!!! tysm have a great day! &lt

Alex Ar [27]

Answer:

Biofuel: Fuel from living matter

Conservertion of energy: It's a law where energy, when bodies/particles touch in a close system stays constant.

Conduction: Where via touch heat/electricity travels to a diffrent thing.

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3 years ago

Suppose that 98.0g of a non electrolyte is dissolved in 1.00kg of water. The freezing point of this solution is found to be -0.4

Sholpan [36]

Answer:

$\large \boxed{\text{392 u}}$

Explanation:

1. Calculate the molal concentration

The formula for the freezing point depression by a nonelectrolyte is

$\Delta T_{f} = -K_{f}b\\b = -\dfrac{\Delta T_{f}}{ K_{f}} = -\dfrac{-0.465 \, ^{\circ}\text{C}}{\text{1.86 $\, ^{\circ}$C$\cdot$kg$\cdot$mol}^{-1}} = \text{0.250 mol/kg}$

2. Calculate the moles of solute

$\begin{array}{rcl}b & = & \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\\text{moles of solute} & = & b \times {\text{kilograms of solvent}}\\n & = &\text{0.250 mol/kg} \times \text{1.00 kg}\\ & = & \text{0.250 mol}\\\end{array}$

3. Calculate the molecular mass

$\begin{array}{rcl}\text{Moles} & = &\dfrac{\text{mass}}{\text{molar mass}}\\\\\text{0.250 mol} & = & \dfrac{\text{98.0 g}}{MM}\\\\MM & = & \dfrac{\text{98.0 g }}{\text{0.250 mol}}\\\\& = &\textbf{392 g/mol}\\\end{array}\\\text{The molecular mass of the solute is $\large \boxed{\textbf{392 u}}$}$

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4 years ago

Which has the least mass<br> proton<br> electron<br> neutron

Katarina [22]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ This would be an electron.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0

3 years ago

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How many moles of a gas sample are in a 10.0 L container at 298 K and 203 kPa? (Use the ideal gas law PV = nRT with R = 8.31 L-k

weeeeeb [17]

Ideal gas law: PV = nRT

P-pressure
V-volume
n-number of moles(m/M)
R-constant
T- temperature

State given info:
V=10L
T=298k
P=203kPa
R=8.31(only for kPa, for pressure at atm use 0.08206)

Sub in:
(203kPa)(10L)=n(8.31)(298)

Rearrange:
n= (203)(10) / (8.31)(298)
n = 0.819745mol in gas sample

8 0

3 years ago