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Nat2105 [25]
3 years ago
8

What is twice of 2^30 using exponents

Mathematics
1 answer:
coldgirl [10]3 years ago
7 0

Answer:

2^31.

Step-by-step explanation:

2 * 2^30

= 2^1 * 2^30

= 2^31. (Law of indices)

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What is the formula to find the rate of discount when M.P and S.P after discount is given.
cupoosta [38]

Answer:

Selling Price = M.P. – Discount = 100 – 5 = Rs. 95. If S.P. is Rs 95, then M.P. is Rs. 100.

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Triangle ABC has side lengths 10, 14, and 26. Do the side lengths form a Pythagorean triple? Explain.
uysha [10]
By <span>Pythagorean triple
a²+b²=c²,
c should be longest side
10²+14²=26²
100+196=676
296</span>≠676
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3 years ago
(40 points to the right answer) Matilda is selling hand-painted vases at a craft fair. She will have to pay $200 to rent a booth
Vlada [557]

Answer:

lol

Step-by-step explanation:

hmmm this is messy

6 0
3 years ago
Please solve the problem ​
jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.

Then you can eliminate <em>Y</em> by taking the sum

4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>

==>   <em>X</em> = (4<em>A</em> + <em>B</em>)/11

Similarly, you can eliminate <em>X</em> by using

-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>

==>   <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11

It follows that

X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}

Similarly, you would find

Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}

You can solve the second system in the same fashion. You would end up with

P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}

3 0
3 years ago
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