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KatRina [158]
3 years ago
12

Select reason(s) why 1-hydroxy-2-methyl-5-isopropylbenzene is an incorrect systematic name for carvacrol.

Chemistry
1 answer:
Keith_Richards [23]3 years ago
4 0

The reason why 1-hydroxy-2-methyl-5-isopropylbenzene is not the correct systematic name for carvacrol is because the substituents are not listed alphabetically.

IUPAC nomenclature provides the correct and acceptable system of naming organic compounds which are internationally acceptable among scientists.

According to the rules of IUPAC nomenclature, compounds are named in alphabetical order. The names of the locants are ordered in such a way that they have the lowest number. Following IUPAC nomenclature, the correct name of the compound ought to be, 1-hydroxy-5-isopropyl-2-methylbenzene.

Learn more: brainly.com/question/11587934

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An archaeologist discovered some charcoal at an excavation site. He sent the samples to a lab for C-14 dating, knowing that the
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In the Haber process for ammonia synthesis, K " 0.036 for N 2 (g) ! 3 H 2 (g) ∆ 2 NH 3 (g) at 500. K. If a 2.0-L reactor is char
lisabon 2012 [21]

Answer : The partial pressure of N_2,H_2\text{ and }NH_3 at equilibrium are, 1.133, 2.009, 0.574 bar respectively. The total pressure at equilibrium is, 3.716 bar

Solution :  Given,

Initial pressure of N_2 = 1.42 bar

Initial pressure of H_2 = 2.87 bar

K_p = 0.036

The given equilibrium reaction is,

                              N_2(g)+H_2(g)\rightleftharpoons 2NH_3(g)

Initially                   1.42      2.87             0

At equilibrium    (1.42-x)  (2.87-3x)     2x

The expression of K_p will be,

K_p=\frac{(p_{NH_3})^2}{(p_{N_2})(p_{H_2})^3}

Now put all the values of partial pressure, we get

0.036=\frac{(2x)^2}{(1.42-x)\times (2.87-3x)^3}

By solving the term x, we get

x=0.287\text{ and }3.889

From the values of 'x' we conclude that, x = 3.889 can not more than initial partial pressures. So, the value of 'x' which is equal to 3.889 is not consider.

Thus, the partial pressure of NH_3 at equilibrium = 2x = 2 × 0.287 = 0.574 bar

The partial pressure of N_2 at equilibrium = (1.42-x) = (1.42-0.287) = 1.133 bar

The partial pressure of H_2 at equilibrium = (2.87-3x) = [2.87-3(0.287)] = 2.009 bar

The total pressure at equilibrium = Partial pressure of N_2 + Partial pressure of H_2 + Partial pressure of NH_3

The total pressure at equilibrium = 1.133 + 2.009 + 0.574 = 3.716 bar

6 0
3 years ago
What was the initial temperature of a gas contained in a 2.0-L bottle at a pressure of 1.00 atm if it was placed under vacuum an
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4 0
3 years ago
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bagirrra123 [75]
There are 1000 grams in a kg.
To convert g to kg, dovide by 1000.

3.5/1000= 0.0035 kg

Final answer: D
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