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Ulleksa [173]
3 years ago
11

The hybridization for the B in Bcl3 is ?

Chemistry
1 answer:
Phoenix [80]3 years ago
6 0

Answer:

sp²

Explanation:

You need to look at how many electron orbitals around the atom.  Looking at the structure below, you can see that there are three electron orbitals.  This gives you an sp² hybridization.

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A student wanted to investigate the effect of light on the growth of
timofeeve [1]

Answer:

D.phototropism

Explanation:

Phototropism is a type of tropism in which a plant or plant part responds to light. According to this question, a student wanted to investigate the effect of light on the growth of cress seedlings. The student used three different pots for the experiment.

Pot 1 was placed with light from above. Pot 2 was placed in a cupboard with no light. Pot 3 was placed in a window with light from one direction only. However, the image attached to this question shows that the plants in the different pots face different directions in response to light, which depicts phototropism

5 0
3 years ago
Suppose that you measured out 3.50g of Na2SO4. how many moles would you have? (show work)​
Ket [755]

Answer:

Na2SO4 is equal to 0.0070401642780093 mole.

Explanation:

5 0
3 years ago
Whats heptane's formula?
Dovator [93]
Heptane means seven carbon atoms and since the general formula is CnH2n+2, heptane will be C7H16
5 0
4 years ago
Which properties represent a metal ( select all that apply )
blagie [28]

Malleable, shiny and good conductors
A B E
4 0
3 years ago
I performed an experiment and mixed copper nitrate and potassium iodide. When they reacted, they formed a precipitate, even thou
Alexus [3.1K]

Answer:

2Cu2^+ + 2I^- ----> 2Cu^+ + I2

Explanation:

The reaction performed in the experiment is;

2 Cu(NO3)2 + 4 KI → 2 CuI (s) + 4 KNO3 + I2

The iodide ions reduces Cu^2+ to Cu^+ which is insoluble in water hence the precipitate. This is so because iodine is a good oxidizing agent seeing that it requires one electron to fill its outermost shell. Potassium on the other hand is a good reducing agent since it easily looses its one electron.

The oxidation - reduction equation is as follows;

2Cu2^+ + 2e ----> 2Cu^+ reduction half equation

2I^- ----> I2 + 2e. Oxidation half equation

Balanced redox reaction equation;

2Cu2^+ + 2I^- ----> 2Cu^+ + I2

3 0
3 years ago
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