Question

Balance the following chemical equation (if necessary):

Answer 1

$\\ \sf\longmapsto SiCl_4+4H_2O\longrightarrow H_4SiO_4+4HCl$

On reactant side

• Si=1
• H=8
• Cl=4
• O=4

On products side

• Si=1
• H=8
• Cl=4
• O=4

Answer 2

Answer: SiCl₄(s) + 4 H₂O(l) → H₄SiO₄(aq) + 4 HCl(aq)

Explanation:
You can pretend there is an imaginary line splitting the chemical equation into two on the arrow to help balance the equation.
Balance out chlorine on both sides, add the coefficient 4 to HCl
now there are 4 chlorines on the left and the right side.
Then, balance out Hydrogen on both sides, add the coefficient 4 to H₂O
now, there are 4*2=8 hydrogens on the left and 4+4=8 hydrogens on the right.
Counting the total number of atoms on both sides of the arrow, the equation is balanced
1 Si = 1 Si
4 Cl = 4 Cl
4 O = 4 O
8 H = 8 H