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Margaret [11]
3 years ago
11

(1-√-4)(-3-√-25) with steps pls

Mathematics
2 answers:
posledela3 years ago
5 0

Answer:-14

Step-by-step explanation:

(1-√-4)(-3-√-25)

[(1*-3)-(1*√-25)-(√-4*-3)-(√-4*√-25)]

(-3)-(-5)-(6)-(10)

-14

meriva3 years ago
5 0

Answer:

-13+i

Step-by-step explanation:

(1-\sqrt{-4} )(-3-\sqrt{-25} )

\left(1-2i\right)\left(-3-5i\right)

\left(1\times \left(-3\right)-\left(-2\right)\left(-5\right)\right)+\left(1\times \left(-5\right)+\left(-2\right)\left(-3\right)\right)i

=-13+i

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3 years ago
Use the identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to determine the sum of the squares of two numbers if the difference of the squ
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Answer:

Step-by-step explanation:

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2

Adding and substracting 2x^2y^2

We get

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2

And we know a^2-2ab+b^2=(a-b)^2

So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2

Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2

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5 0
3 years ago
What is the power of ten in (8.91 x 10^2) (3.3 x 10^12)?
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In this problem, the power of 10 is 14. Hope this helps!
6 0
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How to determine a quotient in simplest form
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d. 5/12÷ 5/6 = 5/12 x 6/5 = 30/60 = 1/2
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6 0
3 years ago
a flower bed is in the shape of a triangle with one side twice the length of the shortest side and the third side is 30 feet mor
yarga [219]
Turn phrases into mathmatical expressions:

"<span>one side(s) twice the length of the shortest side(x)" = 2x
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Answer: 
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8 0
3 years ago
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