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2 years ago

(1-√-4)(-3-√-25) with steps pls

Mathematics

2 answers:

posledela2 years ago

5 0

Answer:-14

Step-by-step explanation:

(1-√-4)(-3-√-25)

[(1*-3)-(1*√-25)-(√-4*-3)-(√-4*√-25)]

(-3)-(-5)-(6)-(10)

-14

meriva2 years ago

5 0

Answer:

$-13+i$

Step-by-step explanation:

$(1-\sqrt{-4} )(-3-\sqrt{-25} )$

$\left(1-2i\right)\left(-3-5i\right)$

$\left(1\times \left(-3\right)-\left(-2\right)\left(-5\right)\right)+\left(1\times \left(-5\right)+\left(-2\right)\left(-3\right)\right)i$

$=-13+i$

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A music store sold 10 to the third CDs and ten to the second CDs players if each CD costs $12 and each CD player costs $35, what

enot [183]

10^3 CDs with CD = $12 then total CDs earnings is (10^3)(12) = $12,000
10^2 CD players with CD plater = $35 then total CD player earnings is (10^2)(12) = $1,200
Total store earnings = ($12,000 + $1,200) = $13,200

4 0

3 years ago

Read 2 more answers

What is the side length of the eectagkes

dedylja [7]

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

1. 5 in and 1/3 in

Here,

$Let\\l=5\\w=\frac{1}{3}\\Area=l*w\\=5*\frac{1}{3}\\=\frac{5}{3}\ in^2$

2. 5 in and 4/3 in

Here,

$l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2$

3. 5/2 in and 4/3 in

$let\\l=\frac{5}{2}\\w=\frac{4}{3}\\Area= \frac{5}{2}*\frac{4}{3}\\=\frac{20}{6}=\frac{10}{3}\ in^2$

4. 7/6 in and 6/7 in

Let

$l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2$

Hence,

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Keywords: Rectangle, Area

Learn more about rectangles at:

#LearnwithBrainly

8 0

3 years ago

Urgent!!!!!!!!!!!!!!!!!!

MAVERICK [17]

24 right box VEDR - 6(4)
9 Left triangle VMR - 0.5 (6)(3)
24 + 9 = 33

6 0

2 years ago

-18m + 27n GCF: Check:

MaRussiya [10]

The answer to 18m + 27n would be

8 0

2 years ago

Please help

Harman [31]

Answer:

we get $\mathbf{gf(2)=-\frac{1}{3}}$

Step-by-step explanation:

We are given:

$f(x)=1-2x\\g(x)= \frac{1}{x}\\h(x)=x^3+1$

We need to find value of $gf(2)$

$gf(2)=g(f(2))$

First putting f(x) inside of g(x) and then putting x=2

$gf(x)=g(f(x))\\gf(x)=\frac{1}{1-2x}$

Now putting x=2 to find $gf(2)$

$gf(x)=\frac{1}{1-2x}\\gf(2)=\frac{1}{1-2(2)}\\gf(2)=\frac{1}{1-4}\\gf(2)=\frac{1}{-3}\\gf(2)=-\frac{1}{3}$

So, we get $\mathbf{gf(2)=-\frac{1}{3}}$

3 0

2 years ago