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Gelneren [198K]
2 years ago
14

Pls help this is due rn!

Mathematics
2 answers:
levacccp [35]2 years ago
7 0
The answer is 7
According to PEMDAS you have to divide 4 and 2
Which is 2 and 2 + 5 gives you 7
77julia77 [94]2 years ago
6 0
The sum of 5 and the quotient of 4 and 2 would be the answer
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Round of the underlined digit in each day decimal number​
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There were 84 people at the party who each had 1 cup of juice. How many quarts of juice were used at the party? (A 12 quarts B 4
Nataly_w [17]

Answer:C

Step-by-step explanation: 84/4=21

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3 years ago
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Aldo spends $14 each time he travels the toll roads. He started the month with $224 in his toll road account. The amount, A
skelet666 [1.2K]
Pare a.) $70 is what he would have left. Since each trip is $14 you would multiply that by the amount of times he went which was 11. 14x11 is $154. But you need what he has left so you take his total amount $224-$154 and get $70.

Part b.) 16 times. He has $224 total. You want to find out how many times he can go on the tool roads. We know the toll roads cost $14 each time. So you do $224/14 and get an even amount of 16. He would be able to use it 16 times before he have no money left.
6 0
2 years ago
Solve the expressions on the left when x=5<br>3x-10<br>x^2-15<br>5x-21<br>x+10-8​
Nitella [24]

Answer:

5

10

4

7

Step-by-step explanation:

Apply the value of x into the expressions:

3(5) - 10 = 15 - 10

           = 5

5² - 15 = 25 - 15

          = 10

5(5) - 21 = 25 - 21

             = 4

5 + 10 - 8 = 15 - 8

               = 7

5 0
2 years ago
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Please help me with question number 2
Mice21 [21]

Answer:

2. The area of the side walk is approximately 217 m²

3. The distance away from the sprinkler the water can spread is approximately 11 feet

4. The area of the rug is 49.6

Step-by-step explanation:

2. The dimensions of the flower bed and the sidewalks are;

The diameter of the flower bed = 20 meters

The width of the circular side walk, x = 3 meters

Therefore, the diameter of the outer edge of the side walk, D, is given as follows

D = d + 2·x (The width of the side walk is applied to both side of the circular diameter)

∴ D  = 20 + 2×3 = 26

The area of the side walk = The area of the sidewalk and the side walk = The area of the flower bed

∴ The area of the side walk, A = π·D²/4 - π·d²/4

∴ A = 3.14 × 26²/4 - 3.14 × 20²/4 = 216.66

By rounding to the nearest whole number, the area of the side walk, A ≈ 217 m²

3. Given that the area formed by the circular pattern, A = 379.94 ft.², we have;

Area of a circle = π·r²

∴ Where 'r' represents how far it can spread, we have;

π·r² = 379.94

r = √(379.94 ft.²/π) ≈ 10.997211 ft.

Therefore, the distance away from the sprinkler the water can spread, r ≈ 11 feet

4. The circumference of the rug = 24.8 meters

The circumference of a circle, C = 2·π·r

Where;

r = The radius of the circle

π = 3.1

∴ For the rug of radius 'r', C = 2·π·r = 24.8

r = 24.8/(2·π) = 12.4/π = 12.4/3.1 = 4

The area = π·r²

∴ The area of the rug = 3.1 × 4² = 49.6.

8 0
2 years ago
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