Answer:
The answer to your question is 6.54 g of H₂O
Explanation:
Data
mass of water = ?
mass of carbon dioxide = 16 g
Balanced chemical reaction
H₂CO₃ ⇒ H₂O + CO₂
Process
1.- Calculate the molar mass of the products
H₂O = (1 x 2) + (1 x 16) = 2 + 16 = 18 g
CO₂ = (1 x 12) + (16 x 2) = 12 + 32 = 44 g
2.- Use proportions and cross multiplication to solve this problem.
18 g of H₂O -------------------- 44 g of CO₂
x -------------------- 16 g of CO₂
x = (16 x 18) / 44
x = 288/44
x = 6.54 g of H₂O
Answer:
Number of moles of KClO3 required to produce 6.9 moles of oxygen gas is 4.6 moles.
Explanation:
The decomposition of potassium trioxochlorate(v) by heat to produce potassium chloride and oxygen gas is given by the balanced chemical equation below;
2KClO3(s) ----> 2KCl(s) + 3O2(g)
From the equation of the reaction, 2 moles of KClO3 produces 3 moles of oxygen gas when it decomposes under standard conditions of temperature and pressure.
The mole ratio of KClO3 to oxygen gas
is 2:3
When 6.9 moles of oxygen gas is produced, (2/3) * 6.9 moles of KClO3 will be required = 4.6 moles of KClO3
Therefore, number of moles of KClO3 required to produce 6.9 moles of oxygen gas is 4.6 moles