Here are the fuel efficiencies (in mpg) of 12 new cars . 28, 14, 48, 22, 14, 18, 52, 36, 32, 20, 12, 55 What is the percentage o
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25% assuming you don’t count the car with 18 mpg fuel efficiency.
if you add the amount of cars up that have less than 18 mpg and then divide it by the total number (12) you will get a decimal (0.25) to find the percent multiply the decimal by 100
Answer:
$960
Step-by-step explanation:
You are going to want to use the simple interest formula for this. The one below is modified for solving the interest earned.

<em>I = interest amount
</em>
<em>P = principal amount
</em>
<em>r = interest rate (decimal form)
</em>
<em>t = time
</em>
The first step is to change 3% into a decimal:
3% ->
-> 0.03
Now, lets plug in the values into the equation:


Jameson will be charged $960 of interest after 4 years.
Answer:
Step-by-step explanation:
1. A car requires 22 litres of petrol to travel a distance of 259.6 km
what is the distance that the car can travel on 63 ltr of petrol
22ltr = 259.6km
63ltr=
cross multiply
{63 x 259.6}/22 = 16354.8/22 = 743.4 km
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km
2. To travel a distance of 2013.2 km
we would need to calculate the amount of fuel
A car requires 22 litres of petrol to travel a distance of 259.6 km
what amount of fuel would it require to travel 2013.2km
22ltr = 259.6km
xltr = 2013.2km
x is the value of petrol to cover 2013.2km
cross multiply
(2013.2 x 22)/259.6
44290.4/259.6 = 170.610169492≈170.6 ltr
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km
if 1ltr is $1.99
170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5
The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5
Answer:
m=1
Step-by-step explanation:
Add 3x is the right answer