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Ulleksa [173]
3 years ago
5

A bus entered the freeway and traveled at a constant speed of 80 mph. Two hours later a second bus followed the first bus, enter

ing the freeway from the same point as the first bus, and traveled at a constant speed of 65 mph. How long will it take the second bus to catch up with the first bus?
Mathematics
1 answer:
Wittaler [7]3 years ago
6 0

Answer:

It will take about 15-20 Minutes to catch up to that bus.

Step-by-step explanation:

65+ 20= 85 so its a tad bit over but it works.

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Simplify (20^13)^19 A. 400^32 B. 20^32 C. 20^247 D. 400^247
vovikov84 [41]
When an exponent is outside the parenthesis, you multiply them.

13*19=247

“C” 2^247 is the answer.

I hope this helps!
~kaikers
5 0
3 years ago
I need an explanation on how to work this out
rjkz [21]

Answer:

make 360×each number given/15 students to start drawing

360×7/15=168°

360×5/15=120°

360×2/15=48°

360×1/15=24°

now draw each one from the radius give to the clockwise

if you don't know what's clockwise direction, see it from your house or tell anybody in your home to tell you where is clockwise

after you finish drawing, label each section by writing the names on the correct sections ( you can write in or out of the circle)

6 0
3 years ago
How can I this math equation -5 -x =-8
Liula [17]

Answer: x = 3

Step-by-step explanation:

-5 -x = -8

-× = -8 + 5

-x = -3

x = 3

6 0
3 years ago
If sinx=2cosx then, what is the value of sin2x?
Travka [436]
          sin(x) = 2cos(x)
         tan(x) = 2
tan⁻¹[tan(x)] = tan⁻¹(2)
                x ≈ 63.4

sin(2x) = sin[2(63.4)]
sin(2x) = sin(126.8)
sin(2x) ≈ 0.801
3 0
3 years ago
Read 2 more answers
What is an equation for a sine curve with amplitude 2, and period 4pi radians ?
Nezavi [6.7K]
<span>1. a sine curve with amplitude 2, and period 4pi radians
</span>
the general equation of the sine curve ⇒⇒ y = a sin (nθ)
where: a is the amplitude  and  n = 2π/perid
∵ <span>amplitude 2, and period 4pi radians
</span>
∴ y = 2 sin (θ/2)

The correct answer is option D. y = 2 sin (θ/2)
===========================================

<span>2.The period and amplitude of the function ⇒⇒ y = 5 cos 2θ
</span>
<span>comparing with y = a cos nθ
</span>
where : a is the amplitude  and  n = 2π/period
<span>amplitude = 5  , period = 2π/n = 2π/2 = π
</span>

The correct answer is option B. Period: pi radians: Amplitude:5

============================================================
3. tan (2π/3) = tan 120° = -√3 
120° lie in the second quadrant and its reference angle = 180° - 120° = 60°
tan function in the second quadrant is negative
∴ tan 120° = - tan 60 = -√3

The correct answer is C. -sqrt3

=====================================================
4. <span>Tan 5π/6 = tan 150° = -(√3)/3
</span>
150° lies in the second quadrant and its reference angle = 180° - 150° = 30°
tan function in the second quadrant is negative
∴ tan 150° = - tan 30 = -(√3)/3

The correct answer is <span>B.-sqrt3/3</span>
8 0
3 years ago
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