(-1,2) is a solution
y>x
2>-1 is correct
in this case yes
x+y≥x
-1+2≥-1
1≥-1 is correct: Yes
in this case no
x+y≥y
1≥2
is not correct. No
Im thinking the answer is c
Answer:
The solution for y is y = 2x + 1
Step-by-step explanation:
* <em>Lets explain how to solve an equation for one of the variables</em>
- We need to solve the equation 16x + 9 = 9y - 2 x for y
- That means we want to find y in terms of x and the numerical term
- the equation has two sides, one side contains x and numerical term
and the other side contains y and x
- We need to separate y in one side, and other term in the other side
* <em>Lets do that</em>
∵ 16x + 9 = 9y - 2x
- Add 2x to both sides to cancel -2x from the right side
∴ 16x + 2x + 9 = 9y - 2x + 2x
- Add like terms in each side
∴ 18x + 9 = 9y
- Divide each term by the coefficient of y ⇒ (÷9)
∴ (18 ÷ 9)x + (9 ÷ 9) = (9 ÷ 9)y
∴ 2x + 1 = y
- Switch the two sides
∴ y = 2x + 1
* The solution for y is y = 2x + 1
Answer:
Solve the rational equation by combining expressions and isolating the variable
x
.
All real numbers
Interval Notation:
−∞,∞)
Step-by-step explanation:
f(-2) = 2(-2)² - 8(-2) + 6 = 30
f(-1) = 2(-1)² - 8(-1) + 6 = 16
f(0) = 2(0)² - 8(0) + 6 = 6
f(1) = 2(1)² - 8(1) + 6 = 0
f(2) = 2(2)² - 8(2) + 6 = -2