12:1
There is always going to be 12 times more T-shirts than cartons
Answer:
.
Step-by-step explanation:
Given : Sample size : n= 64 , the sample is a large sample (n>30), so we can apply z-test.
Sample mean = 
Standard deviation : 
Level of confidence:

Then, critical z-value =
The confidence interval to estimate the population mean is given by :_


Hence, the 95% confidence interval to estimate the population mean can be computed as
.
<h3>Given Equation:</h3>
6 - 2n = -4n - 2 - 8
<h3>To Find:</h3>
The value of n.
<h3>Solution:</h3>
6 - 2n = -4n - 2 - 8
or, -2n + 4n = -2 - 8 - 6
or, 2n = -16
or, n = -16/2
or, n = -8
<h2>Answer:</h2>
The value of n is -8.
Probability that a randomly selected adult has an IQ less than 137 is 0.9452
<u>Step-by-step explanation:</u>
<u>Step 1: </u>
Sketch the curve.
The probability that X<137 is equal to the blue area under the curve.
<u>Step 2:
</u>
Since μ=105 and σ=20 we have:
P ( X<137 )=P ( X−μ<137−105 )= P(X−μ/ σ< 137−105/20 )
Since x−μ/σ=Z and 137−105/20=1.6 we have:
P (X<137)=P (Z<1.6)
<u>Step 3: </u>
Use the standard normal table to conclude that:
P (Z<1.6)=0.9452
∴ probability that a randomly selected adult has an IQ less than 137 is 0.9452.
<u>9</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>solution</u><u>.</u>
Answer:
Solution given:
2x+10=28
subtracting both side by 10
2x+10-10=28-10
2x=18
dividing both side by 2
2x/2=18/2
x=9