Write the nuclear decay equation for the alpha particle decay of Pu-243
1 answer:
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Answer:
3.80*10⁻³ moles of HCl can be produced from 0.226 g of SOCl₂
Explanation:
The balanced reaction is:
SOCl₂ + H₂O ----> SO₂ + 2 HCl
By stoichiometry of the reaction they react and produce:
- SOCl₂: 1 mole
- H₂O: 1 mole
- SO₂: 1 mole
- HCl: 2 mole
Being:
- S: 32 g/mole
- O: 16 g/mole
- Cl: 35.45 g/mole
- H: 1 g/mole
the molar mass of the compounds participating in the reaction is:
- SOCl₂: 32 g/mole + 16 g/mole + 2*35.45 g/mole= 118.9 g/mole
- H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole
- SO₂: 32 g/mole + 2*16 g/mole= 64 g/mole
- HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
Then, by stoichiometry of the reaction, the following amounts of mass react and are produced:
- SOCl₂: 1 mole* 118.9 g/mole= 118.9 g
- H₂O: 1 mole* 18 g/mole= 18 g
- SO₂: 1 mole* 64 g/mole= 64 g
- HCl: 2 mole* 36.45 g/mole= 72.9 g
Then the following rule of three can be applied: if by stoichiometry of the reaction 118.9 grams of SOCl₂ produce 2 moles of HCl, 0.226 grams of SOCl₂ how many moles of HCl do they produce?
moles of HCl= 3.80*10⁻³
<u><em>3.80*10⁻³ moles of HCl can be produced from 0.226 g of SOCl₂</em></u>
Answer:- and
Explanations:- In the first equation, the oxidation number of O is decreasing from 0 to -2 where as the oxidation number of H is increasing from 0 to +1. As the oxidation number is increasing for one element(H) and decreasing for other element(O), it is an oxidation-reduction reaction.
Second reaction is a double displacement reaction so there is no change to the oxidation numbers of the elements and hence it is not oxidation-reduction reaction.
In third reaction, the oxidation number of Al is increasing from 0 to +3 and the oxidation number of H is decreasing from +1 to 0. Here again there is an increase and decrease to the oxidation numbers of two elements, it is oxidation-reduction reaction.
fourth and fifth reactions are again double displacement reactions and so there is no change to oxidation numbers for any of the elements and they are not the oxidation-reduction reactions.
So, the only correct equations are and
.
Answer:
Explanation:
First of all the chemical formula
The chemical is named Lead(IV)Phosphate.