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ruslelena [56]
3 years ago
5

Boiling and evaporation aren't the same. Can you explain the difference????? ☺

Chemistry
2 answers:
xxTIMURxx [149]3 years ago
6 0
Evaporation usually occurs on the surface. Evaporation may occur when the partial pressure of vapor of a substance is less than the equilibrium vapour pressure. Boiling is a phase transition from the liquid phase to gas phase that occurs at or above theboiling temperature.
pishuonlain [190]3 years ago
6 0
Boiling is when you like Cook and bubbles come in the water that's boiling 
evaporation is when something is really hot and a kind of a really hot smoke comes out if the pot 
that is an evaporation
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Which step of desalination must be done before water is condensed and collected?
USPshnik [31]

the water is heated until it evaporates

6 0
2 years ago
Cuando un gas que se encuentra a 20°c se calienta hasta los 40°c sin que varie su presion, su volumen se duplica
kati45 [8]

Answer:

Not doubled

Explanation:

The equation below represent the ideal gases relationship

PV ÷ T = constant

Here

P denotes pressure,

V denotes volume,

T denotes temperature in degrees Kelvin

Now

20 ° c = 273 + 20

= 293 K

And,

40 ° c = 313 K

So,

V = Vo. 313 K ÷  293 K = 1.07 Vo

So,  the volume is NOT doubled.

In the case when the temperature would be determined in degrees celsius at 0 degrees so the volume would be zero

4 0
3 years ago
An atom of gold has a mass of 3.271 X 10-22 g. How many atoms of gold are in 5.00 g of gold? (Give your answer in scientific not
Kobotan [32]

Answer:

1.53 × 10²² atoms Ag

Explanation:

Step 1: Define conversions

3.271 × 10⁻²² g = 1 atom

Step 2: Use Dimensional Analysis

5.00 \hspace{3} g \hspace{3} Ag(\frac{1 \hspace{3} atom \hspace{3} Ag}{3.271(10)^{-22} \hspace{3} g \hspace{3} Ag} ) = 1.52858 × 10²² atoms Ag

Step 3: Simplify

We have 3 sig figs.

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5 0
3 years ago
Do plasmids have an importance beyond the practice of genetic engineering?
kozerog [31]
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4 0
2 years ago
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jekas [21]
The third question requires you to solve for the weight of sodium (Na) and weight of Chloride (Cl) from the calculated moles of each element Na, and Cl.

So, you need to multiply the calculated moles of Na with its molar mass (23 g/ mol) to get the answer for Na. And multiply the calculated moles of Cl with its molar mass (35.45 g/mol) to get the answer for Cl. 
6 0
3 years ago
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