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alina1380 [7]
3 years ago
10

Which best explains why a scientist would share these details in a conference

Chemistry
1 answer:
STALIN [3.7K]3 years ago
5 0

Answer: It informs the audience if the study included controlled tests.

Explanation: Usually, scientific conferences involve presentation of papers by scientists. These paper presentations are actually the sharing of details of the scientific research carried out by other scientists.

Presenting the materials and methods section of the a research project  to a scientific conference informs the audience if the study included controlled tests.

The inclusion of controlled tests in a scientific study enhances the validity of the results obtained in the study.

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Nitric oxide can be oxidized in air to form nitrogen dioxide. At normal atmospheric concentrations this is a very slow process.
lawyer [7]

Answer:

exothermic

Explanation:

This is an exothermic reaction because you can see the 232.4 kJ at the end of the reaction. That means that 232.4 kilo-joules are released when the reaction happens; when energy is released during a reaction, the reaction is exothermic.

Tell me if you need anything else! :)

6 0
4 years ago
Gaseous compound Q contains only xenon and oxygen. When 0.100 gg of Q is placed in a 50.0 mLmL steel vessel at 0 ∘C∘C, the press
asambeis [7]

The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.229 atm. What is the likely formula of the compound?

A. XeO

B. XeO_4

C. Xe_2O_2  

D. Xe_2O_3

E. Xe_3O_2

<u>Answer:</u> The chemical formula of the compound is XeO_4

<u>Explanation:</u>

To calculate the molecular mass of the compound, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{w}{M}RT

where,

P = Pressure of the gas = 0.229 atm

V = Volume of the gas  = 50.0 mL = 0.050 L     (Conversion factor:  1 L = 1000 mL)

w = Weight of the gas = 0.100 g

M = Molar mass of gas  = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gas = 0^oC=273K

Putting value in above equation, we get:

0.229\times 0.050=\frac{0.100}{M}\times 0.0821\times 273\\\\M=\frac{0.100\times 0.0821\times 273}{0.229\times 0.050}=195.4g/mol\approx 195g/mol

The compound having mass as 195 g/mol is XeO_4

Hence, the chemical formula of the compound is XeO_4

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