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ziro4ka [17]
3 years ago
11

Concentrations expressed as a percent by mass are useful when the solute is a _____.

Chemistry
2 answers:
elixir [45]3 years ago
4 0

Answer:

Solid

Explanation:

A solid such as sugar can be measured and added to a solute to form a solution. The amount of solute present can be expressed as a percentage.

Westkost [7]3 years ago
3 0

C. Solid

Although molarity is commonly used to express concentrations for reactions in solution or for titrations, it does have one drawback—molarity is the number of moles of solute divided by the volume of the solution, and the volume of a solution depends on its density, which is a function of temperature.

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In a solution, which pair of actions could combine to keep a concentration constant?
insens350 [35]

Answer:

B: Adding water, then adding solute

Explanation:

This is because, say you have a solution with a certain concentration.

If you add more water, it will become more diluted (less concentrated)

If you add more solute, it will become more concentrated.

Therefore if you add water and solute, it could cancel out, and the concentration would remain the same.

Hope this helps! Let me know if you have any questions/ would like anything further explained :)

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Which type of organism helps return nutrients from dead plants and animals to the soil. A producer. B prey. C predator. D decomp
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The answer is D. Decomposer
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How are sex cells different from body cells
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8 0
3 years ago
What is the density of a book with a mass of 60g and a volume of 20 cm3?
Vaselesa [24]

Answer:

2.5 g/cm3 .

Explanation:

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6 0
3 years ago
PLEASE HELP!! A gas has a volume of 7.9 L at a temperature of 222. K and pressure of 877 mmHg. What is the new temperature (in C
Natali5045456 [20]

Answer:

82.97 K

Explanation:

Applying,

PV/T = P'V'/T'................ Equation 1

Where P = initial pressure, T = Initial temperature, V = Initial Volume, P' = Final pressure, V' = Final Volume, T' = Final Temperature.

Make T' the subject of formula in equation 1

T' = P'V'T/PV................ Equation 2

From the question,

Given: P = 877 mmHg = (877×0.001316) atm = 1.154 atm, T = 222.2 K, V = 7.9 L, P' = 0.327 atm, V' = 10.41 L

Substitute these values into equation 2

T' = (0.327×10.41×222.2)/(1.154×7.9)

T' = 82.97 K

Hence the new temperature is 82.97 K

7 0
3 years ago
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