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3 years ago

What is the equation for determining gas pressure?

Chemistry

2 answers:

Advocard [28]3 years ago

8 0

Answer:

Explanation:

First, let's review the ideal gas law, PV = nRT. In this equation, 'P' is the pressure in atmospheres, 'V' is the volume in liters, 'n' is the number of particles in moles, 'T' is the temperature in Kelvin and 'R' is the ideal gas constant (0.0821 liter atmospheres per moles Kelvin)

igomit [66]3 years ago

4 0

You might be interested in

A titanium cube contains 3.10•10^23 atoms. The density of a titanium is 4.50g/cm^3. What is the edge length of the cube?

Lerok [7]

Answer:

1.76cm

Explanation:

We'll begin by calculating the mass of titanium that contain 3.10x10²³ atoms. This can be obtained as follow:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10²³ atoms. This implies that 1 mole of titanium also contains 6.02x10²³ atoms.

1 mole of titanium = 48g

Now, if 48g of titanium contains 6.02x10²³ atoms,

Then Xg of titanium will contain 3.10x10²³ atoms i.e

Xg of titanium = (48x3.10x10²³)/6.02x10²³

Xg of titanium = 24.72g

Next, we shall determine the volume of the titanium. This is illustrated below:

Density of titanium = 4.50g/cm³

Mass of titanium = 24.72g

Volume of titanium =..?

Density = Mass /volume

Volume = Mass /Density

Volume of titanium = 24.72g/4.50g/cm³

Volume of titanium = 5.49cm³

Finally we shall determine the edge length of the titanium cube as follow:

Volume = L³

5.49cm³ = L³

Take the cube root of both side

L = 3√(5.49cm³)

L = 1.76cm

Therefore, the edge length is 1.76cm

5 0

3 years ago

The primary role of the nervous system is to:

Scrat [10]

Gather and respond to information

3 0

2 years ago

The ksp of pbbr2 is 6.60× 10–6. what is the molar solubility of pbbr2 in 0.500 m kbr solution

Alex_Xolod [135]

The solubility of PbBr₂(s) with the presence of 0.500 M of KBr is 2.64 x 10⁻⁵ M.

4 0

3 years ago

Read 2 more answers

Help me plz, I need help on this.

kirza4 [7]

Omg i lost everything ugh
To do it again

1. 12g+2(16g)= 44g/mol
25.01/ 44g/mol= .... mol

2. 14g+3(1g)= 17g/mol
34.05g/ 17g/mol=.... mol

3. 23g+1g+ 12g+ 3(16g)= 84g/mol
17.31g/ 84g/mol=.... mol

4. 6(12g)+12(1g)+6(16g)= 180g/mol
123.44g/ 180g/mol=.... mol

5. 23g+16g+1g= 40g/mol
2.2mol x 40g/mol= .... g

6. 2(35g)= 71g/mol
4.5mol x 71g/mol= .... g

7. 137g+ 2(14g)+ 6(16g)= 261g/mol
0.002mol x 261g/mol= ....g

8. 2(56g)+ 3(32g)+ 12(16g)= 400g/mol
5.4mol x 400g/mol=.... g

I cant believe i had to do this all over

4 0

3 years ago

Balance the following Equation:

pashok25 [27]

Answer:

HCl

Explanation:

Given data:

Mass of Zn = 50 g

Mass of HCl = 50 g

Limiting reactant = ?

Solution:

Chemical equation:

Zn + 2HCl → ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = mass / molar mass

Number of moles = 50 g/ 65.38 g/mol

Number of moles = 0.76 mol

Number of moles of HCl:

Number of moles = mass / molar mass

Number of moles = 50 g/ 36.5 g/mol

Number of moles = 1.4 mol

Now we will compare the moles of Reactant with product.

Zn : ZnCl₂

1 : 1

0.76 : 0.76

Zn : H₂

1 : 1

0.76 : 0.76

HCl : ZnCl₂

2 : 1

1.4 : 1/2×1.4 = 0.7

HCl : H₂

2 : 1

1.4 : 1/2×1.4 = 0.7

Less number of moles of product are formed by HCl it will act limiting reactant.

6 0

3 years ago