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Alinara [238K]
2 years ago
5

suppose you find a website that describes rusting of a nail as a change to only the physical properties of iron. would it be acc

urate
Chemistry
1 answer:
Kaylis [27]2 years ago
5 0

Answer:

The website is inaccurate.

Explanation:

Remember, a chemical change is characterized by many things, but most commonly:

  1. A change in color, temperature or state.
  2. An irreversible change
  3. One or more new substances are formed

Rusting (Iron oxide) is a redox reaction (Oxidation-Reduction Reaction) where  iron molecules come in contact with water and oxygen molecules. The iron molecules lose electrons, becoming oxidized, while oxygen gains electrons, becoming reduced.

Is rust reversable? (No)

Did the colour of the iron on the surface change? (Yes)

Did a new substance form? (Yes, Read above).

Hope I helped! Have a good day!

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Answer: a

Explanation:

Bc I just did it and yeah

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How many grams are there in 2.4 moles of CaCO3?
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What volume (mL) of 0.135 M NaOH is required to neutralize 13.7 mL of 0.129 M HCl? a: 0.24 b: 13.1 c: 0.076 d: 6.55 e: 14.3
Len [333]

Answer:

The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).

Explanation:

The reaction between an acid and a base is called neutralization, forming a salt and water.

Salt is an ionic compound made up of an anion (positively charged ion) from the base and a cation (negatively charged ion) from the acid.

When an acid is neutralized, the amount of base added must equal the amount of acid initially present. This base quantity is said to be the equivalent quantity. In other words, at the equivalence point the stoichiometry of the reaction is exactly fulfilled (there are no limiting or excess reagents), therefore the numbers of moles of both will be in stoichiometric relationship. So:

V acid *M acid = V base *M base

where V represents the volume of solution and M the molar concentration of said solution.

In this case:

  • V acid= 13.7 mL= 0.0137 L (being 1,000 mL= 1 L)
  • M acid= 0.129 M
  • V base= ?
  • M base= 0.135 M

Replacing:

0.0137 L* 0.129 M= V base* 0.135 M

Solving:

V base=\frac{0.0137 L*0.129 M}{0.135 M}

V base=0.0131 L = 13.1 mL

<u><em> The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).</em></u>

4 0
3 years ago
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zheka24 [161]

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Convert 12.64 g of NaOH to moles
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3 years ago
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