The answer is
<span>
only carboxyl groups (=C=OO-</span>
Answer:
(S)-3-methoxy-3-methylbutan-2-ol
Explanation:
In this case, we have an <u>epoxide opening in acid medium</u>. The first step then is the <u>protonation of the oxygen</u>. Then the epoxide is broken to generate the most <u>stable carbocation</u>. The nucleophile (
) will attack the carbocation generating a new bond. Finally, the oxygen is <u>deprotonated</u> to obtain an ether functional group and we will obtain the molecule <u>(S)-3-methoxy-3-methylbutan-2-ol</u>.
See figure 1
I hope it helps!
Answer : The metal used was iron (the specific heat capacity is
).
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.


where,
= specific heat of unknown metal = ?
= specific heat of water = 
= mass of unknown metal = 150 g
= mass of water = 200 g
= final temperature of water = 
= initial temperature of unknown metal = 
= initial temperature of water = 
Now put all the given values in the above formula, we get


Form the value of specific heat of unknown metal, we conclude that the metal used in this was iron (Fe).
Therefore, the metal used was iron (the specific heat capacity is
).
Answer:
Ammonia, urea, uric acid
Explanation:
The given compounds are:-
Urea which has a molecular formula of
and has 2 atoms of nitrogen per molecule.
Ammonia which has a molecular formula of
and has 1 atom of nitrogen per molecule.
Uric acid which has a molecular formula of
and has 4 atoms of nitrogen per molecule.
Thus,
The order from least to most nitrogen is:-
Ammonia, urea, uric acid