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Alla [95]
3 years ago
15

Determine the mass of the H2CO3 produced.

Chemistry
1 answer:
FrozenT [24]3 years ago
7 0

Answer:

62.03 g/mol

Explanation:

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Acetylene gas (ethyne; HC = CH) burns in an oxyacetylene torch to produce carbon dioxide and water vapor. The heat of reaction f
Yanka [14]

The mass of CO2 produced by 26g of acetylene is 88g.

Given ,

In an oxyacetylene torch, acetylene gas (ethyne; HCCH) burns to produce carbon dioxide and water vapour.

The acetylene combustion reaction is given by,

H2O + HCCH + 5/2 O=O 2CO2

Heat of reaction for acetylene combustion = 1259kj/mol

CO2 has a molecular mass of 44g/mol.

2 moles of CO2 have a molecular mass of 88g.

On combustion, 1 mole of acetylene yields 2 moles of CO2.

Thus, 26g of acetylene produces 88g of CO2 when burned.

As a result, the mass of carbon dioxide produced by 26g of acetylene is 88g.

Learn more about acetylene here :

brainly.com/question/15346128

#SPJ4

6 0
1 year ago
Water is known as the universal solvent. One reason water makes a good solvent is because it is composed of polar molecules. Wha
Flauer [41]

Answer: Option (C) is the correct answer.

Explanation:

A water molecule is made up of two hydrogen atoms and one oxygen atom. Its molecular formula is H_{2}O.

It is known that hydrogen is electropositive in nature whereas oxygen is electronegative in nature. Therefore, oxygen will pull the electron of hydrogen towards itself as a result, there will be formation of partial positive charge on hydrogen and partial negative charge on oxygen atom.

Thus, the water molecule becomes polar. So, we can conclude that water molecule is a polar molecule because water molecules have a positive charge on one end and a negative charge on  the other.

5 0
3 years ago
Which reaction leads to the formation of a precipitate?
Brrunno [24]

2Ca(OH)2(aq) + 2FeCl3(aq) on the dead locs

6 0
3 years ago
Read 2 more answers
A bubble of helium gas has a volume of 0.65 L near the bottom of a large
Flura [38]

Answer:

0.73L

Explanation:

The following data were obtained from the question :

V1 = 0.65 L

P1 = 3.4 atm

T1 = 19°C = 19 + 273 = 292K

V2 =?

P2 = 3.2 atm

T2 = 36°C = 36 + 273 = 309K

The bubble's volume near the top can be obtain as follows:

P1V1 /T1 = P2V2 /T2

3.4 x 0.65/292 = 3.2 x V2 /309

Cross multiply to express in linear form as shown below:

292 x 3.2 x V2 = 3.4 x 0.65 x 309

Divide both side by 292 x 3.2

V2 = (3.4 x 0.65 x 309) /(292 x 3.2)

V2 = 0.73L

Therefore, the bubble's volume near the top is 0.73L

8 0
3 years ago
Which is best option?
Ilia_Sergeevich [38]
The first option Forsure .
7 0
2 years ago
Read 2 more answers
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