Question

N204(0) + 2NO2(g)

Answer 1

setup 1 : to the right

setup 2 : equilibrium

setup 3 : to the left

Further explanation

The reaction quotient (Q) : determine a reaction has reached equilibrium

For reaction :

aA+bB⇔cC+dD

$\tt Q=\dfrac{C]^c[D]^d}{[A]^a[B]^b}$

Comparing Q with K( the equilibrium constant) :

K is the product of ions in an equilibrium saturated state  

Q is the product of the ion ions from the reacting substance  

Q <K = solution has not occurred precipitation, the ratio of the products to reactants is less than the ratio at equilibrium. The reaction moved to the right (products)

Q = Ksp = saturated solution, exactly the precipitate will occur, the system at equilibrium

Q> K = sediment solution, the ratio of the products to reactants is greater than the ratio at equilibrium. The reaction moved to the left (reactants)

Keq = 6.16 x 10⁻³

Q for reaction N₂O₄(0) ⇒ 2NO₂(g)

$\tt Q=\dfrac{[NO_2]^2}{[N_2O_4]}$

Setup 1 :

$\tt Q=\dfrac{0.0064^2}{0.098}=0.000418=4.18\times 10^{-4}$

Q<K⇒The reaction moved to the right (products)

Setup 2 :

$\tt Q=\dfrac{0.0304^2}{0.15}=0.00616=6.16\times 10^{-3}$

Q=K⇒the system at equilibrium

Setup 3 :

$\tt Q=\dfrac{0.230^2}{0.420}=0.126$

Q>K⇒The reaction moved to the left (reactants)

Answer 2

Answer:

The system will shift toward the products

The system is at equilibrium

The system will shift toward the reactants

Explanation:

This is correct on edg... Good Luck!!!!