2 years ago

How can you overcome drawback of a chemaicl equation ? any three

1 answer:

4 0

Answer:

1.rate of reaction should be indicated by symbols 2.we should indicate physical states by sybloms 3.reversible reaction should be indicated by using double arrows

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Consider the following thermochemical reaction for kerosene:

ch4aika [34]

We have to solve this question using the stoichiometry of the reaction:

The equation of the reaction is;

$2 C12H26(l) + 37 O2(g) -----> 24 CO2(g) + 26 H2O(l) + 15,026 kJ$

According to the question;

Number of moles of CO2 released = 21.3 g/44 g/mol = 0.48 moles

From the stoichiometry of the reaction:

Since;

24 moles of CO2 released 15,026 KJ

0.48 moles of CO2 will release 0.48 * 15,026/24

= 301 KJ of heat.

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7 0

2 years ago

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If 11g of a gas occupies 5.6dm'3at s.t.p., calculate it's vapour density (1.0mol of a gas occupies 22.4dm'3at s.t.p.).

11111nata11111 [884]

Answer:

${ \boxed{ \bf{vapour \: density = 2 \times molecular \: mass}}} \\{ \tt{ PV= (\frac{m}{ m_{r}}) RT}} \\ { \tt{3 \times 5.6 = \frac{11}{m _{r}} \times 0.0831 \times 273}} \\ { \tt{m _{r} = 14.85 \: g}} \\ \\ { \bf{vapour \: density = 2 \times m _{r}}} \\ = 2 \times 14.85 \\ = 29.7 \: { \tt{g {dm}^{ - 3} }}$