Answer:
1. 15
2. 8
Step-by-step explanation:
The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)
The nth term of a GP is;
Tn = ar^(n-1)
Where;
a = first term
r = common ratio
For the first sequence;
The common ratio r is
r = T3/T2 = 540/90 = 6
r = 6
T2 = ar^(2-1) = ar
T2 = 90 = ar
Substituting the values of r;
90 = a × 6
a = 90/6
a = 15
First term = 15
2. The sam method applies here.
Common ratio r = T3/T2 = 128/32 = 4
r = 4
T2 = ar^(2-1) = ar
T2 = 32 = ar
Substituting the values of r;
32 = a × 4
a = 32/4
a = 8
First term = 8
Answer:
no
Step-by-step explanation:
If it is not a perfect square, then the original number cannot be a perfect square. 125 is not a perfect square [nor is 53 or 35], so 1953125 cannot be a perfect square.
Answer:
eeee
Step-by-step explanation:
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Answer:
w = 60
Step-by-step explanation:
the midsegment SU is half the measure of side RV , then
SU = 
RV , so
w - 30 = w ( multiply through by 2 to clear the fraction )
2w - 60 = w ( subtract w from both sides )
w - 60 = 0 ( add 60 to both sides )
w = 60
Divide the numerator with the denominator for each, and that's all really... Good luck!!
