y = x³ + 3x² - x - 3
0 = x³ + 3x² - x - 3
0 = x²(x) + x²(3) - 1(x) - 1(3)
0 = x²(x + 3) - 1(x + 3)
0 = (x² - 1)(x + 3)
0 = (x² + x - x - 1)(x + 3)
0 = (x(x) + x(1) - 1(x) - 1(1))(x + 3)
0 = (x(x + 1) - 1(x + 1))(x + 3)
0 = (x - 1)(x + 1)(x + 3)
0 = x - 1 or 0 = x + 1 or 0 = x + 3
+ 1 + 1 - 1 - 1 - 3 - 3
1 = x or -1 = x or -3 = x
Solution Set: {-3, -1, 1}
Answer:
13
Step-by-step explanation:
8/2=16/4
=4
x-3=2.5*4
x=10+3
x=13
Answer:
The Answer is 10! (I Don't know if you meant 2x5 or 2x5x28) If I am wrong please let me know! If you meant 2x5x28 the answer is 280!
Step-by-step explanation:
Answer:
The correct answer is D.
Step-by-step explanation:
Given:
General equation of second degree
x² + y² + 14 x + 2 y + 14 = 0
We must transform given equation to the canonical form from which we will read requested data.
The canonical form of the circle equation is:
(x - p)² + (y - q)² = r²
Where p and q are the coordinates of the center of the circle and r are radius. (p,q) = (x,y)
x² + 2 · x ·7 + 7² - 7² + y² + 2 · y · 1 + 1 - 1 + 14 = (x+7)² + (y+1) - 49 - 1 + 14 = 0
(x + 7)² + (y + 1)² = 36
We see that p = - 7 , q = - 1 and r = 6
God with you!!!
Answer:
x=34
Step-by-step explanation:
