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Inga [223]
3 years ago
10

Solve each scientific notation PLEASE HELP!!!!!!

Mathematics
2 answers:
vaieri [72.5K]3 years ago
7 0

Answer:

  1. A-610000
  2. A-.0043
  3. A-21000

Step-by-step explanation:

1. =6.1*105

=6.1*(10*10*10*10*10)

=610000

2. =0.43*10−2

=0.43* 1 /10*10

=0.0043

3. 2.1(104)

=2.1*104

=2.1*(10*10*10*10)

=21000

Scrat [10]3 years ago
4 0

Answer:

below

Step-by-step explanation:

#1:) 610,

#2:) 4300

for thousand three hundred

#3:) 21,000

(I belive that's it)

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What are the domain and range of the function f(x) = 2^x+1?
scoundrel [369]

Answer:

Domain: (-∞, ∞)

 Range: (0,∞)

Step-by-step explanation:

Exponential functions are curves which approach a horizontal asymptote usually at y=0 or the x-axis unless a value has been added to it. If it has, the curve shifts. This function has addition on the exponent but not to the whole function so it does not change the asymptote. Its y - values remain between 0 and ∞. This is the range, the set of y values.

However, the range of exponentials can change based on the leading coefficient. If it is negative the graph flips upside down and its range goes to -∞. This doesn't have it either.

The addition to 1 on the exponent shifts the function to the left but doesn't change the range.

In exponential functions, the x values are usually not affected and all are included in the function. Even though it shifts, the domain doesn't change either. Its domain is (-∞, ∞).

Domain: (-∞, ∞)

 Range: (0,∞)

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3 years ago
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Step-by-step explanation:

7 0
3 years ago
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What is the distance between (3,-9) and (6,-2)?
exis [7]

Answer:

7/3

Step-by-step explanation:

y2-y1/x2-x1

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8 0
3 years ago
1/6 5/6<br><br> &lt;<br> &gt;<br> =<br> or none
Rudik [331]
The answer is < :) hope this helped
5 0
3 years ago
a new car, originally worth $35,795, depreciates at a rate of 17% per year. The value of the car can be represented by the equat
Sergio [31]

We have been given that a new car, originally worth $35,795, depreciates at a rate of 17% per year. The value of the car can be represented by the equation y=35795(0.83)^x, where x represents the number of years since purchase and y represents the value (in dollars) of the car.

To find the value of car of after 5 years, we will substitute x=5 in our given equation as:

y=35795(0.83)^5

y=35795\cdot (0.3939040643)

y=14099.79598

Upon rounding to nearest tenth, we will get:

y\approx 14099.8

Therefore, the car will be worth $14,099.8 after 5 years it is first purchased.

Since $14,099.8 is less than original value of car, therefore, we know hat value of car is depreciating and $14,099.8 is correct answer.

We also know that an exponential decay function is in form y=a(1-r)^x, where,

y = Final value after t years,

a = Initial value,

r = Decay rate in decimal form,

x= Time.

17\%=\frac{17}{100}=0.17

y=35795(1-0.17)^x

y=35795(0.83)^x

8 0
3 years ago
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