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bonufazy [111]
3 years ago
8

Your password must be created only using the numbers 0 to 9 with repeated numbers allowed. If your password is four numbers long

, how many ways can you create a password? Do not include commas in your answer, for example, 1,000 would be written as 1000.
Mathematics
1 answer:
mina [271]3 years ago
4 0

Answer:

10000

Step-by-step explanation:

yeah-ya ...... right?

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The sum of a number and 4.7 is 8.1.
Sloan [31]

<em>Greetings from Brasil...</em>

Be that unknown number X

Then we can write the following expression:

X + 4.7 = 8.1

<h2>X = 3.4</h2>

5 0
4 years ago
-5(-x - 1) + 4x – 1= 49<br> solve for x
Anton [14]

Answer:

x=5

Step-by-step explanation:

-5(-x - 1) + 4x – 1= 49

Distribute

5x +5 +4x -1 = 49

Combine like terms

9x +4 = 49

Subtract 4 from each side

9x+4-4 = 49-4

9x = 45

Divide by 9

9x/9 =45/9

x = 5

4 0
3 years ago
Read 2 more answers
Please answer<br><br> Quickly
Mashcka [7]
The answer is 21

By comparing the 4 vertices you can determine the rectangle x-length and y-length. The coordinate for the vertice is:
1,+4i
-2, +4i
-2, -3i
1, -3i

From the coordinate, you can see there are 2 x coordinate(1 and -2) and 2 y coordinate(4i and -3i) that used.
The x-length would be: 1 - (-2)= 3
The y-length would be: 4i- (-3i)= 7i

Then the area of the rectangle would be:
area= x-length * y-length= 3*7=21
8 0
3 years ago
M^2 + 2m - 15 =0 sorry
agasfer [191]
(m   -   3)(m   +   5)= 0
m= {3, -5}
3 0
3 years ago
If sally got 28 questions correct and received 70% on the exam, how many questions were on the exam
Furkat [3]

Answer: 40

Step-by-step explanation:

Number of correct questions Sally got = 28 questions

Percentage of correct questions answered= 70% on the exam,

Total number of questions in the exam = Unknown

Let the total questions in the exam be represented as y.

Since Sally got 70% correctly, this will be:

70% of y = 28

70/100 × y = 28

0.7 × y = 28

0.7y = 28

Divide both side by 0.7

0.7y/0.7 = 28/0.7

y = 40

There are 40 questions in the exam.

7 0
3 years ago
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